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The current source provides a current of is(t) = (4 + 4e3*)u(t) Amp. Find the inductor current and the inductor voltage v(t) for t>0.

The current source provides a current of is(t) = (4 + 4e3*)u(t) Amp. Find the inductor current and the inductor voltage v(t) for t>0.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Answer:

iL(t) = -3.2e-t/2 + 4 – 0.8e-3t Amp, where t is in seconds

v = 12.8e-t/2 + 19.2e-3t Volt

**Chapter 7 Problem 60** The current source provides a current of \( i_s(t) = (4 + 4e^{-3t})u(t) \) Amp. Find the inductor current and the inductor voltage \( v(t) \) for \( t>0 \). **Circuit Diagram Explanation:** - The circuit features a parallel configuration of three components: - A 5 Ω resistor - An 8 H inductor - A 20 Ω resistor - The current source providing \( i_s(t) \) is oriented upwards on the left side of the circuit. - The voltage across the inductor is labeled as \( v(t) \) with polarity indicated as positive at the top and negative at the bottom near the 20 Ω resistor. **Current Function:** - \( i_s(t) = (4 + 4e^{-3t})u(t) \) represents a step function current source that begins providing current at \( t > 0 \). **Objective:** - Calculate the current through the inductor and the voltage across it for \( t > 0 \).
Transcribed Image Text:**Chapter 7 Problem 60** The current source provides a current of \( i_s(t) = (4 + 4e^{-3t})u(t) \) Amp. Find the inductor current and the inductor voltage \( v(t) \) for \( t>0 \). **Circuit Diagram Explanation:** - The circuit features a parallel configuration of three components: - A 5 Ω resistor - An 8 H inductor - A 20 Ω resistor - The current source providing \( i_s(t) \) is oriented upwards on the left side of the circuit. - The voltage across the inductor is labeled as \( v(t) \) with polarity indicated as positive at the top and negative at the bottom near the 20 Ω resistor. **Current Function:** - \( i_s(t) = (4 + 4e^{-3t})u(t) \) represents a step function current source that begins providing current at \( t > 0 \). **Objective:** - Calculate the current through the inductor and the voltage across it for \( t > 0 \).
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