3. Assume the input to the circuit below is given by 3sin(2лft) Volts, where f-1000 Hz. What does this circuit do? What would you call this circuit? Assume the diode is ideal with FBV=0 V. Plot Vout vs. the input for two cycles. D sine 1 kHz ww 100 Q + + ww 100 Q Diode Op-amp Vout
3. Assume the input to the circuit below is given by 3sin(2лft) Volts, where f-1000 Hz. What does this circuit do? What would you call this circuit? Assume the diode is ideal with FBV=0 V. Plot Vout vs. the input for two cycles. D sine 1 kHz ww 100 Q + + ww 100 Q Diode Op-amp Vout
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Transcribed Image Text:**Question:**
3. Assume the input to the circuit below is given by \(3\sin(2\pi ft)\) Volts, where \(f=1000 \text{ Hz}\). What does this circuit do? What would you call this circuit? Assume the diode is ideal with \(FBV=0 \text{ V}\). Plot \(V_{out}\) vs. the input for two cycles.
**Circuit Description:**
The circuit consists of:
- A sine wave generator with a frequency of 1 kHz as the input source.
- A resistor of 100 ohms connected in series with a diode.
- A diode is present in the circuit, oriented with its anode connected to the resistor and cathode towards the output.
- An operational amplifier (Op-amp) arranged in an unspecified configuration.
- Output \(V_{out}\) is taken across the Op-amp.
**Explanation:**
This circuit appears to be a basic half-wave rectifier using an op-amp. Here's how it works:
1. **Sine Wave Input:** The input is a 3 V peak sine wave with a frequency of 1 kHz.
2. **Diode Functionality:** The diode, being ideal with a forward bias voltage (FBV) of 0 V, will only allow the positive half-cycles of the sine wave to pass through, blocking the negative half-cycles.
3. **Op-amp Role:** The exact configuration of the op-amp is not specified, but it might be used to amplify or buffer the rectified signal.
**Outcome:**
The circuit functions as a **half-wave rectifier**, converting AC input into a pulsating DC output by blocking negative cycles of the input waveform.
**Graphical Explanation:**
1. **Input Signal:** A continuous sine wave oscillating between +3V and -3V.
2. **Output Signal \(V_{out}\):** Only the positive half of the sine wave is passed, appearing as a series of positive pulses every half-cycle.
For visualization, plot the input sine wave for two cycles and show the rectified output as intermittent positive pulses corresponding to the positive half-cycles.
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