The compound bar shown below is made of a light, strong material with E = 70,000 N/mm². Two forces are applied to the rigid plates connecting the bars. The yield strength is oy = 200 N/mm². The bar has a rectangular cross section with height H = 12.5 mm and thickness t =1.0 mm. You may neglect the weight of the bars. (a) Calculate the x-direction internal force in segments AB and BC of the compound bar. Show all work. (b) Calculate the total length change of the compound bar. (c) The plane 1-2 represents a lap joint. Calculate the normal stress on the lap joint. L₂= 625 mm 1 H=12.5 mm A L₁=775 mm H = 12.5 mm =1800 N =35° 2 F₂=1000 N Cross section H-1 12.5 mm t = 1.0 mm

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Problem 15
The compound bar shown below is made of a light, strong material with E= 70,000 N/mm². Two forces are applied to
the rigid plates connecting the bars. The yield strength is o, = 200 N/mm². The bar has a rectangular cross section
with height H = 12.5 mm and thickness t = 1.0 mm. You may neglect the weight of the bars.
(a) Calculate the x-direction internal force in segments AB and BC of the compound bar. Show all work.
(b) Calculate the total length change of the compound bar.
(c) The plane 1-2 represents a lap joint. Calculate the normal stress on the lap joint.
L₂= 625 mm
A
L₁ = 775 mm
H = 12.5 mm
X
1800 N
B
1
H = 12.5 mm
=35° 2
F₂ = 1000 N
Cross section
H-12
H = 12.5 mm
t = 1.0 mm
Transcribed Image Text:Problem 15 The compound bar shown below is made of a light, strong material with E= 70,000 N/mm². Two forces are applied to the rigid plates connecting the bars. The yield strength is o, = 200 N/mm². The bar has a rectangular cross section with height H = 12.5 mm and thickness t = 1.0 mm. You may neglect the weight of the bars. (a) Calculate the x-direction internal force in segments AB and BC of the compound bar. Show all work. (b) Calculate the total length change of the compound bar. (c) The plane 1-2 represents a lap joint. Calculate the normal stress on the lap joint. L₂= 625 mm A L₁ = 775 mm H = 12.5 mm X 1800 N B 1 H = 12.5 mm =35° 2 F₂ = 1000 N Cross section H-12 H = 12.5 mm t = 1.0 mm
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Given;

E=70000 N/mm2σy=200 M/mm2H=12.5 mmt=1.00 mm

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