The center of mass of the arm shown in the figure is at point A. Find the magnitudes (in N) of the tension force F and the force F, which hold the arm in equilibrium. (Let 8 = 24.0°.) Assume the weight of the arm is 48.3 N. IF 8.00 cm 29.0 cm 1₂ 354 X Draw a diagram showing the forces and distances. Find the sum of the torques about point O, and set this equal to zero. Solve your equation for F₁. N 340.30 X Apply Newton's second law in the x and y directions, and solve for F Pythagorean theorem to calculate F. . N Sx and F . You will need your value of F. Then use the sy'

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The diagram illustrates an arm held in equilibrium by two forces: the tension force (\( \vec{F}_\text{T} \)) and the support force (\( \vec{F}_\text{s} \)). The arm's center of mass is located at point A. The angle θ is given as 24.0°, and the weight of the arm is 48.3 N.

Key Measurements and Details:

- Distance from point O to the center of mass (A): 29.0 cm
- Distance from point O to the line of action of \( \vec{F}_s \): 8.00 cm

To solve the problem, the following steps should be taken:

1. **Draw a Diagram:** Clearly illustrate the forces and distances. Sum the torques around point O and set this sum to zero to solve for \( F_T \).

2. **Calculate \( F_T \):** The given value is 354 N (though it seems an error is noted), indicating the need to verify calculations.

3. **Apply Newton's Second Law:** In both x and y directions, solve for the components \( F_{sx} \) and \( F_{sy} \) using the calculated \( F_T \).

4. **Use Pythagorean Theorem:** Finally, calculate the magnitude of \( \vec{F}_s \) using its components. The provided value is 340.30 N, which might also need verification or correction.

This calculation involves understanding torque, the equilibrium of forces, and vector components within a given physical system.
Transcribed Image Text:The diagram illustrates an arm held in equilibrium by two forces: the tension force (\( \vec{F}_\text{T} \)) and the support force (\( \vec{F}_\text{s} \)). The arm's center of mass is located at point A. The angle θ is given as 24.0°, and the weight of the arm is 48.3 N. Key Measurements and Details: - Distance from point O to the center of mass (A): 29.0 cm - Distance from point O to the line of action of \( \vec{F}_s \): 8.00 cm To solve the problem, the following steps should be taken: 1. **Draw a Diagram:** Clearly illustrate the forces and distances. Sum the torques around point O and set this sum to zero to solve for \( F_T \). 2. **Calculate \( F_T \):** The given value is 354 N (though it seems an error is noted), indicating the need to verify calculations. 3. **Apply Newton's Second Law:** In both x and y directions, solve for the components \( F_{sx} \) and \( F_{sy} \) using the calculated \( F_T \). 4. **Use Pythagorean Theorem:** Finally, calculate the magnitude of \( \vec{F}_s \) using its components. The provided value is 340.30 N, which might also need verification or correction. This calculation involves understanding torque, the equilibrium of forces, and vector components within a given physical system.
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