The boiling point of water H,O is 100.0°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in water is antifreeze (ethylene glycol). How many grams of antifreeze, CH,0HCH;OH (62.10 g/mol), must be dissolved in 249.0 grams of water to raise the boiling point by 0.500 °C ? Refer to the table for the necessary boiling or freezing point constant. Solvent Formula Kp C/m) Kf(°C/m) Water H20 0.512 1.86 Ethanol CH;CH2OH 1.22 1.99 Chloroform CHCI3 3.67 Benzene 2.53 5.12 Diethyl ether CH3CH,OCH,CH3 2.02 g antifreeze,
The boiling point of water H,O is 100.0°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in water is antifreeze (ethylene glycol). How many grams of antifreeze, CH,0HCH;OH (62.10 g/mol), must be dissolved in 249.0 grams of water to raise the boiling point by 0.500 °C ? Refer to the table for the necessary boiling or freezing point constant. Solvent Formula Kp C/m) Kf(°C/m) Water H20 0.512 1.86 Ethanol CH;CH2OH 1.22 1.99 Chloroform CHCI3 3.67 Benzene 2.53 5.12 Diethyl ether CH3CH,OCH,CH3 2.02 g antifreeze,
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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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The boiling point of water H,0 is 100.0°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in water is antifreeze (ethylene glycol).
How many grams of antifreeze, CH,OHCH,OH (62.10 g/mol), must be dissolved in 249.0 grams of water to raise the boiling point by 0.500 °C ?
Refer to the table for the necessary boiling or freezing point constant.
Solvent
Formula
K, (°C/m) Kf(°C/m)
Water
H20
0.512
1.86
CH3CH,OH
CHCI3
Ethanol
1,22
1.99
Chloroform
3.67
Benzene
2,53
5.12
Diethyl ether CH3CH,OCH,CH3
2,02
g antifreeze.
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Transcribed Image Text:[References]
Use the References to access important values if needed for this question.
The boiling point of water H,0 is 100.0°C at 1 atmosphere. A nonvolatile, nonelectrolyte that dissolves in water is antifreeze (ethylene glycol).
How many grams of antifreeze, CH,OHCH,OH (62.10 g/mol), must be dissolved in 249.0 grams of water to raise the boiling point by 0.500 °C ?
Refer to the table for the necessary boiling or freezing point constant.
Solvent
Formula
K, (°C/m) Kf(°C/m)
Water
H20
0.512
1.86
CH3CH,OH
CHCI3
Ethanol
1,22
1.99
Chloroform
3.67
Benzene
2,53
5.12
Diethyl ether CH3CH,OCH,CH3
2,02
g antifreeze.
Submit Answer
Retry Entire Group
7 more group attempts remaining
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9
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}
G
H
J
%3D
K
Expert Solution
Step 1 :-
When a non volatile solute is added to a pure solvent its boiling point increases
The difference in boiling point of solution to that of pure solvent is known as elevation of boiling point (∆Tb)
Experimentally it was found that elevation of boiling point is directly proportional to molality of the solution
Mathematical relation is
∆Tb = Kb×m
Kb = boiling point constant
m = molality
molality(m) = n/W
n = moles of solute
W = mass of solvent in.Kg
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