The bearing of a back tangent of a simple curve is N 65°00' E, while the forward tangent has a bearing of S 75° 00' E. The tangent distance is 50.00 m. The stationing of the Point of Curvature is at 10 + 235.48. h. Stationing of Vertex (PI) i. Stationing of Point of Tangency (PT) j. Length of Chord from PC to Station A (10+30

Q: PROBLEM 3 Given: (Use Arc Basis) 11 = 18⁰, 12 = 25⁰ T₁ = 100 m t₁ = 32 m Station PT at 12+628 PC…

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Q: The line connecting the PC and PT of the simple curve is 120.4m. The radius is 213.6m. If the…

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Q: A simple curve connects two tangents AB and BC with bearings N 85°30'00" E and S 68°30'00"E,…

A: "Since you have posted a question with multiple sub-parts, we will solve first three sub- parts for…

Q: with the tangent of the first and the second curves respectively. The length of chord from PC to PCC…

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Q: Draw the moment diagram for the beam. Click on "add discontinuity" to add discontinuity lines. Then…

A: Given : Required : Shear and moment diagram

Q: A horizontal curve is designed with a '500' m radius. The curve has a tangent length of 120 m and…

A: Radius of curve = 500 mTangent length = 120 mStationing of PI = 3 + 140 mDeflection angle  = ◇(…

Q: 1. The intersection of two proposed tangent AB and CD are inaccessible. Therefore, from point E…

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Q: 2. A compound curve has the following properties: ,= 25-degree, D,= 6.2-degree, I½= 36-degree, D2=…

A: Given: The value of I1 is 25o. The value of D1 is 6.2o. The value of I2 is 36o. The value of D2 is…

Q: The azimuth of the tangents of the simple curve is 514 degrees and 759 degrees respectively. The…

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Q: If the length of the parabolic curve is 10 meters, Point PI is 5 meters away from Point PC,…

A: True. The point of intersection is always at the half length of parabolic curve

Q: nd BC with bearings 58deg 30' E respec e vertex is 4+360.2

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Q: A simple curve connects two tangents XY and YZ. The survey data are the following: Bearing of XY = N…

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Q: a. Elements of the curve b. Stationing of P.C. and P.T. c. Lengths of sub-chords and its…

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Q: The curve y= x* bounds the shaded 600 section on top. The vertical lines X = 2 in. and x = 5 in.…

A: Given Data: The equation of the curve is y=x4. The limit of curve in X-direction is 2 in. to 5 in.…

Q: 2. A circular curve has the following known elements: Middle Ordinate = 2 m Length of Long Chord =…

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Q: a. Elements of the curve b. Stationing of P.C. and P.T. c. Lengths of sub-chords and its…

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Q: Given the following data: g1=+5% g2=-4% L=80m sta.PC=5+120 elev.PC=105.42m. Determine (a) sta. and…

A: The grade of upgrade, g1 = +5%The grade of downgrade, g2 =-4%Station of PC =5+120Elevation of PC,…

Q: SITUATION 6: The length of common tangent of a compound horizontal curve is 630 m. Di = 3°, l = 50°,…

A: Data for compound curve is given

Q: The tangents of a simple curve have bearings of N. 20° E. and N. 80° E. respectively. The radius of…

A: E = R [ Sec(∆2) - 1 ] R = Radius = 200 m ∆ = 80 - 20 = 60° E = 200 [ Sec(602)-1 ] = 30.94 m

Q: The railroad track is laid out parallel to the forward tangent of the simple curve at a…

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Q: Solve Problems by the moment-areamethod. EI is constant. Compute the slope at A and the…

A: For calculating slope at A and deflection at D in this question the following steps are shown. We…

Q: the horizontal distance from the center of long chord is 2.75 m, what is the offset distance from…

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Q: The deflection angle from PC of two points A and B on a simple curve are 3°15’ and 8°15’,…

A: Given data: Deflection angle PC to A = 3∘15' PC to B=8∘15' The chord distance between A and B is 40m

Q: to connect three lines thus forming the center line of a new road. The lines are AB = 60.2 m, BC =…

A: According to given data  A reversed curve is to connect three lines thus forming the center line of…

Q: Four simple curves (CURVE1, CURVE2 & CURVE3) are connected to form the highway curves. CURVE2 formed…

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Q: a. The maximum probable length of the parabolic curve b. The location and elevation of the lowest…

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Q: Sta. PT of a compound curve is at 15 + 480. I¡ = 30°, I2 = 36°, D¡ = 4°, D2 = 5°. a. What is the…

A: Consider the free body diagram; Calculate the degree of curve is given as;…

Q: 1. 1. A simple curve connects two tangents AB and BC with bearings N 85 deg 30' E and S68deg 30' E…

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Q: A simple curve connects two tangents AB and BC with bearing N 85°30' E and S 68°30' E, respectively.…

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Q: Given the following elements of the compound curve shown: h = 37° 30' I2 = 53° 50' R1 = 250 m. %3D…

A: T1=215m

Q: The elements of the compound curve are as follows: (use arc basis) 11 = 18° D1 = 2° D2 = 4° 12 =…

A: Given : l1 = 18°                         D1 = 2°l2 = 23.5°                     D2 = 4° The…

Q: nects two tangents AB and BC with bearings N 85 deg 30 min E and S 68 deg 30 min E respectively. If…

A: Given:- AB and BC with bearings N 85 deg 30 min E and S 68 deg 30 min E stationing of the Vertex is…

Q: Curves E B Problem: T1 T1 Three curves are to be connected. Data are obtained in the field as…

A: Curve made up of two or more circular arcs of successively shorter or longer radii, joined…

Q: H.w-Curves.p... > Calculate the chainage of the tangent points of the compound curve from the…

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Q: In the reversed curved shown, the central angles of the first and second branches of the curve are…

A: I1 = 28o30' I2 = 44o10' R2 = 125m

Q: The formula V = a End-Area-Method 5. Prismoidal Formula (A₁+ 4Am + A₂) to approximate the volume of…

A: 1.The formula V = L/6 (A1 + 4Am + A2)This is called as Prismoidal Formula. It is used to approximate…

Q: compound curve is at 15 +480, 1₁-30, 1₂-36, D₁-4°, D=5" t is the sta. of the vertex of the compound…

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Q: The elements of a compound curve are as follows: 11 = 18 12 = 23.5 D1 = 2 D2 = 4 If STA PT =…

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Q: The deflection angles of points A and B from the tangent through P.C of a simple curve are 3°05' and…

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Q: Prepare the data for the layout of the given reverse curve by deflection method with the given…

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Q: Probiem A simple curve connects two tangents AB and BC with bearings N 75012' E and S 78036' E,…

A: "Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…

State Plane Coordinate Systems

The state plane coordinate system (SPCS or SPS) is a collection of 124 coordinate systems or geographic zones prepared for particular regions of the U.S. Every state consists of one or more than one state plane zone, the boundaries of which generally follow the county lines. Inside the U.S., there are 110 zones in total, 10 more zones in Alaska, 5 in Hawaii, and 1 for Puerto Rico and US Virgin islands. The system is extensively used for geospatial and geographic data assembling by the state and local governments.