The beam, which is made of a W250x28 profile (1=39.9x106 m4) has a constant distributed load w = 1 kN/m, length L₁ = 6 m, elastic modulus E₁ =200 GPa, and is supported by the fixed wall at B and the rod connected at L₁/2. If the rod has a cross sectional area of 104 m², lenght L2 = 3 m and the material has a modulus of elasticity E2-70 GPa, determine the force in the rod. T L2 W C Lu L1/2 B

The beam, which is made of a W250x28 profile (1=39.9x106 m4) has a constant distributed load w = 1 kN/m, length L₁ = 6 m, elastic modulus E₁ =200 GPa, and is supported by the fixed wall at B and the rod connected at L₁/2. If the rod has a cross sectional area of 104 m², lenght L2 = 3 m and the material has a modulus of elasticity E2-70 GPa, determine the force in the rod. T L2 W C Lu L1/2 B

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter11: Columns

Section: Chapter Questions

Problem 11.5.10P: Solve the preceding problem (W 250 × 44.8) if the resultant force P equals 110 kN and E = 200 GPa.

See similar textbooks

Similar questions

The steel box wrench (E=29,000ksi, v=0.32) is loaded with a 40-lb horizontal force and a 25-lb vertical force. Find the following for an element located at point B on Section a-a: 24 in. 1. The non-vanishing resultant internal moments on section a-a are which of the following? 4 in. a. (160 i- 600 j+960 k)in · Ib b. (-160 i+600 j+960 k ) in · lb c. (-960 i+160 j+600 k)in - lb d. (-960 i -160 ј-600 k)in-lb a e. none of the above 2. The normal and shear force components on section a-a are: a. V, = 65lb;V, = 40lb; N¸ = 25lb b. V, = 0;V, =40lb; N, = 25lb c. V, = 64;V, = 25lb; N, = 40lb d. V, =0;V, =-40lb; N¸ = -25lb e. none of the above 3. The non-vanishing stress components at point B are: 0̟ =1.60; t =-4.89ksi; а. 0, =-4.89; 7 =3.60ksi; 0, = 2.50ksi; T, d. o, = 4.91ksi; t =-4.89ksi; b. с. =-4.89ksi; е. none of the above 4. The principal stresses at point B from most tensile to most compressive are: O1,02,0; =4.16,–0.8,–5.76 b. o,,0,,0, =5.76,0,–4.16 а. O1,02,0; =1.9,-2.45,-6.8 с. d.…
The uniform 44 kN bar BC is supported by a pin at C and the aluminum wire AB. The cross-sectional area of the wire is 178.5 mm2. Assuming bar BC to be rigid, find the vertical displacement of B due to the weight of the bar. Use E = 71 GPa for aluminum. Anwer must be in mm.
Please answer all parts of the question. Thank you so much
M y A 2L - 30% В Calculate the support reaction at the roller at A to the nearest whole number. Use up and to the right as positive, down and to the left if negative. M = 63 KN-m P = 143 KN x = 2 y = 7 L = 5 m
A light ridig member AB is pinned at A and is further supported by light elastic rods CD and GF, member AB supports a 5000lb load at B the elastic modulus for the two elastic rods CD and GF is given as E= 30x106 psi and the cross-sectional area for each of these rods is 1 in2. what are the forces in the two supporting elastic rods as a results of the loading?
A steel beam with length 4 m is to be connected between two columns (Column A and Column B) as shown in Figure 1. This beam is found to be short by 2 mm. Determine the force needed to pull the beam so that it can be connected at the two columns. The cross-section of the beam is shown in Figure 2. Column A Column B L= 4 m 50 mm a uniform thickness 5 Веат mm 100 mm 2 mm Ebeam = 210 kN/mm? Section a-a 2 m 3 m Figure 1 Figure 2
An L-shaped beam is being supported by a ball and socket support at O and two cables, ABand CD. A 100 N force is applied downward in the middle of AC. Draw the FBD for solvingthis rigid body equilibrium question. No need to solve the whole question orwrite the problem-solving steps. Justdraw the FBD.
2-12. For the truss shown in the figure, deter- mine the total elongation of the member BC due to the application of the force P = 450 kN. The || member BC is made from steel and is 60 mm² in cross-sectional area. E = 210 000 MN/m². %3| B 1.20 m D 450 kN 5 spaces at 0.90 m = 4.50 m %3D
PROBLEM 4: Find the reaction force components at point A and B. The member AB has a length of L=10m. The infinitesimal loads at point A and B are 1200N/m and 800N/m respectively. 12=5mm 1200 N/m/ A In L=10m 4₁=5m 0:38 800 N/m
The structure in the sketch below consists of the two members ABC and CDE which are pin- connected at point C. The complete structure is supported by a weightless link at B and a fixed support at E. The link is perpendicular to part BCDE and pin-connected to the support at the bottom. The distributed loading acts perpendicular to the inclined part AB. The figure is not to scale. 600 N/ m A 900N 0.5m E C -1.3т- * 1m - 1m 1.2m Calculate the support reactions that develop on the frame at points B and E. Interpret your final answers on a separate complete free-body diagram of the structure ABCDE. B,
The rigid bar ABC is supported by pin at A and aluminum wire BD, is horizontal before the Load P is applied. Find the vertical displacement of point C caused by the load P=35KN. Where E of aluminum equals 70GPA and the area of the wire is 200mm^2 -Draw and label the diagram correctly, No diagram in the solution will be marked wrong. -Shortcut solution will be marked wrong.- Direction of the assumption of the equilibrium equation must be shown, no direction will be marked wrong.
Figure 4-26/27 Full Alternative Text *4-28. The rod has a slight taper and length L. It is suspended from the ceiling and supports a load P at its end. Show that the displacement of its end due to this load is 8 = PL/(TET ₂1). Neglect the weight of the material. The modulus of elasticity is E. Prob. 4-28 12. 11 P L