The rectangular plate ABCD undergoes deformation as shown with the dashed lines. Find the average shearstrain Yay at A with respect to the x and y axes. The values for the parameters are given here:parametermmLAB300LAD200δι2бг5ByδηCLABBY NO SA2021 Cathy ZupkeAt A Yay =ALAD↑ 82

Sure, The image shows a rectangular plate ABCD that has undergone deformation, and we are asked to…

Answered: The rectangular plate ABCD undergoes…

Mechanics of Materials (MindTap Course List)

9th Edition

ISBN:9781337093347

Author:Barry J. Goodno, James M. Gere

Publisher:Barry J. Goodno, James M. Gere

Chapter7: Analysis Of Stress And Strain

Section: Chapter Questions

Problem 7.7.19P: During a test of an airplane wing, the strain gage readings from a 45° rosette (see figure) are as...

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The plane stress displacement field for the pure bending problem was given by u = - El v = (vy? + x² - P), where -1
The answer is one of the options below please solve carefully and circle the correct option Please write clear .
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Calculate the stiffness matrix for the Q8 element shown below. Make use of the shape functions in natural coordinates and the Jacobian calculated in previous problems. Use 2x2 Gaussian numerical integration. Use plane strain conditions (for unit thickness) with E=200E9 (MPa) and nu=0.25. The final answers is F1= 0.18452e12. I have attached my matlab code below. Please look thru it and correct it. Thanks. u=sym('u') %%ztav=sym('v') %%eta x1=1x2=2x3=3.5x4=3.6x5=4.0x6=2.3x7=1.2x8=0.8 y1=1y2=1y3=1.3y4=2.3y5=3.3y6=3.2y7=3.0y8=2.0X=[x1;x2;x3;x4;x5;x6;x7;x8]Y=[y1;y2;y3;y4;y5;y6;y7;y8]%% diff of ztaDN1Du=1/4*(1-v)*(2*u+v);DN2Du=-u*(1-v);DN3Du=1/4*(1-v)*(2*u-v);DN4Du=1/2*(1-v^2);DN5Du=1/4*(1+v)*(2*u+v);DN6Du=-u*(1+v);DN7Du=1/4*(1+v)*(2*u-v);DN8Du=-1/2*(1-v^2); %% diff of etaDN1Dv=1/4*(1-u)*(2*v+u);DN2Dv=-1/2*(1-u^2);DN3Dv=1/4*(1+u)*(2*v-u);DN4Dv=-v*(1+u);DN5Dv=1/4*(1+u)*(2*v+u);DN6Dv=1/2*(1-u^2);DN7Dv=1/4*(1-u)*(2*v+u);DN8Dv=-v*(1-u);%% find dx/du dx/dv, dy/du and dy/dva=[DN1Du, DN2Du, DN3Du,…
Calculate the stiffness matrix for the Q8 element shown below. Make use of the shape functions in natural coordinates and the Jacobian calculated in previous problems. Use 2x2 Gaussian numerical integration. Use plane strain conditions (for unit thickness) with E=200E9 (MPa) and nu=0.25. I have attached my matlab code below. Please look thru it and correct it. Thanks. u=sym('u') %%ztav=sym('v') %%eta x1=1x2=2x3=3.5x4=3.6x5=4.0x6=2.3x7=1.2x8=0.8 y1=1y2=1y3=1.3y4=2.3y5=3.3y6=3.2y7=3.0y8=2.0X=[x1;x2;x3;x4;x5;x6;x7;x8]Y=[y1;y2;y3;y4;y5;y6;y7;y8]%% diff of ztaDN1Du=1/4*(1-v)*(2*u+v);DN2Du=-u*(1-v);DN3Du=1/4*(1-v)*(2*u-v);DN4Du=1/2*(1-v^2);DN5Du=1/4*(1+v)*(2*u+v);DN6Du=-u*(1+v);DN7Du=1/4*(1+v)*(2*u-v);DN8Du=-1/2*(1-v^2); %% diff of etaDN1Dv=1/4*(1-u)*(2*v+u);DN2Dv=-1/2*(1-u^2);DN3Dv=1/4*(1+u)*(2*v-u);DN4Dv=-v*(1+u);DN5Dv=1/4*(1+u)*(2*v+u);DN6Dv=1/2*(1-u^2);DN7Dv=1/4*(1-u)*(2*v+u);DN8Dv=-v*(1-u);%% find dx/du dx/dv, dy/du and dy/dva=[DN1Du, DN2Du, DN3Du, DN4Du, DN5Du, DN6Du,DN7Du,…
The shear stress-shear strain diagram for a material is shown. The bolt used to hold the lap joint is made of this material and has a diameter of 0.35 in. The material has a Poisson's Ratio of 0.2. T (ksi) F T1 G = Values for the figure are given in the following table. Note the figure may not be to scale. Variable T1 Y1 Value 40 ksi 0.003 rad 71 -7 (rad) a. Determine the Shear Modulus of the allow, G. b. Determine the Elastic Modulus of the allow, E. c. Determine the force required to cause the material to yield, F. Round your final answers to 3 significant digits/figures. ksi
Q1
The following results were dtaimed during a mild steel test piece of 122mm diateret and 50 mm gauge lenythi %3B lis 28 8 12 |0-0210.0310.04 10:05 10-06 1008 Load 20 24 Esttemsion (mm? lo-01 1. Oraw the load extenfion graph and from. the graph determine', i Strain and stress at elastic limit The modulus of elasticity for the mild stel. ii The utimate tensile fest Iv. The Safety factor.
area is 779.1 mm^2, sigma_x is 120.6497159, sigma_y is 0, tau_xy is 0, and Beta is 20 degrees
The stress-strain diagram of a reinforcement steel having a cross-sectional diameter of 12 mm diameter and 100 mm gage length is determined after its tensile strength test as follows. Based on the stressstrain diagram determine the followings properties of the material (Poisson’s ratio of the material is 0.32) :
Calculate the Virtual Condition of the PIN in the drawing below: 1.000 O 1.000 .504 .982 C 1.008 2.000 Ø.995-1.000 +0.008MABC 6.00 O None of these answers is correct X 3.000 01.005-1.030 +0.005MABC B A .XX = .01 ANGLES= ± 1°
3

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