The beam shown in (Figure 1) supports a distributed live load of 1.5 kN/m and single concentrated load of 9 kN. The dead load is 3 kN/m. Follow the sign convention. The distributed live load can be applied to several segments of the beam that are not necessarily adjacent. 2 m 2 m 2 m

Q: Determine the maximum shearing stress and bending stress for the beam loading shown. Box your…

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Q: simply supported beam AB has a length of 3 m and carries distributed load which ies in linear manner…

A: Given:- L=3m UVL=1.5w To find:- w

Q: Determine the flexural stress and shear stress of the beam loaded as shown in the figure.

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Q: Question 4a Determine the resultant force of the linearly-varying distributed load indicated in the…

A: Given : Determine the resultant force of the linearly varying distributed load and compute…

Q: In (Eigure 1), take that uy = 2.5 kN/m. igure 3 m- Wo 1.5 m 1 of 1 > ▼ Part A Replace the…

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Q: figure below: 1. Drive the shear force and bending moment equation and then draw them 2. Find the…

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Q: A beam shown on the figure is subjected to a uniform load of 5 kN/m. Determine the minimum shearing…

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Q: 20 mm 60 mm 20 mm Figure Q4 - Beam Cross-Section ws oz ww 09 20 mm

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Q: The overhanging beam supports the loads as shown in the figure. Determine the maximum shear stress…

A: Consider the figure,

Q: A simply supported beam having a length of 11.5 m, carrying a uniformly distributed dead load of 6…

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Q: For the beam shown in Fig. Determine the value of the distributed load W if the maximum shear stress…

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Q: 2. The cross section of an idealised thin wall symmetrical wing box beam is shown in Figure Q2. The…

A: Given data: Point load=1 kN e=250 mm E=70 GPa G=25 GPa   It is asked to calculate: 1. Shear flow…

Q: 5 kN 5 kN - 5 kN/m B I m 1m 1 m

A: Given, b = 100 m h = 250 mm

Q: +2m R₁ Wo 3m R₂ T 25 mm k 200 mm 25 mm 250 mm 25 mm

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Q: distributed

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Q: From the given system as shown. Solve for the axial deformation in the middle 50 AN 100 N 100 AN…

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Q: A cross section through a wooden beam 200mm side by 220mm deep is shown in figure 3a. The beam has…

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Q: Figure 3a shows the loading, shear force diagram and bending moment diagram of a simply-supported…

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Q: Question 2 . resultant internal shear force of 18 kN. A beam has a rectangular cross section and it…

A: Given data : Shear force (V)=18 KNWidth (B)=140 mmDepth (D)=200 mm

Q: Determine the maximum positive shear in kN. Note: In your solution, draw the shear diagram and box…

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Braced cuts

The braced cut is a method of providing lateral support to the soil in foundation trenches, to prevent the trenches from deformation by the caving in of soil and resisting it from moving laterally. During shallow excavation in firm soil, generally, slopes are provided to resist the caving in of soil. During shallow excavation in soft soil and deep excavation, the chances of caving in of soil increase. Hence, it becomes necessary to make a provision to resist the deformation of trenches due to caving in of soil. The braced cut is the method used for such conditions. The excavation using braced cuts is a bit uneconomical as compared to the traditional open-cut excavation method but provides better safety than the cut excavation method.