I5 The bar shown in the figure below is rotating about a fixed pivot. At a point in time the angularvelocity of the bar is 4 rad/s. The velocity of the free end of the bar, A, can be written as:0.3 m0.4 mOv = -2kOv = 0.4i – 0.8jOv = 1.2i – 1.6j%3DOv = -1.2i +1.6j

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The bar shown in the figure below is rotating about a fixed pivot. At a point in time the angula velocity of the bar is 4 rad/s. The velocity of the free end of the bar, A, can be written as: 0.3 m 0.4 m Ov = -2k Ov = 0.4i – 0.8j Ov = 1.2i – 1.6j v = -1.2i + 1.6j

The bar shown in the figure below is rotating about a fixed pivot. At a point in time the angula velocity of the bar is 4 rad/s. The velocity of the free end of the bar, A, can be written as: 0.3 m 0.4 m Ov = -2k Ov = 0.4i – 0.8j Ov = 1.2i – 1.6j v = -1.2i + 1.6j

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

The bar shown in the figure below is rotating about a fixed pivot. At a point in time the angular
velocity of the bar is 4 rad/s. The velocity of the free end of the bar, A, can be written as:
0.3 m
0.4 m
Ov = -2k
Ov = 0.4i – 0.8j
Ov = 1.2i – 1.6j
%3D
Ov = -1.2i +1.6j

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