Please show every step to the solution. Write it neatly and clearly so that it is easy to follow. Thanks! Through load analysis, force and moment diagram are obtained, as shown below. Diagram below showsthe intensity of the of axial force and torque alone the length of the shaft. (forces are in kN)(a) At point B, C, and E calculate the equivalent stresses in preparation for determining the fatiguesafety factor.(b) For a reliability of 99%, estimate the safety factor of the shaft at points B, C, and E. The above left drawing shows a countershaft with helical gear B, bevel gear D, and two supportingbearing A and C. Loads acting on the bevel gear are shown. Force on the helical gear can be determinedfrom equilibrium of moments about the shaft axis plus the given proportions of helical gear forcecomponents. Shaft dimensions are given in the above right drawing. All shoulders fillets (at points wherediameter changes) have a radius of 5 mm. note that the shaft is designed so that only bearing A takesthrust. The shaft is made of hardened steel, Su=1069 MPa, Sy=896MPA. All important surfaces arefinished by grinding. (Note: stress concentration)ВForces act at 500-mm dia.DF = 1.37 kNAВ550F, = 5.33 kN- 400F; = 0.3675F,F, = 0.2625F,400450F = 1.37 kN(1)Forces act at 375-mm dia.120 dia.EКeyway80 dia.

The force that occurs between mating gears is normal to the surfaces in contact. The axial force Fa,…

Through load analysis, force and moment diagram are obtained, as shown below. Diagram below shows the intensity of the of axial force and torque alone the length of the shaft. (forces are in kN) (a) At point B, C, and E calculate the equivalent stresses in preparation for determining the fatigue safety factor. (b) For a reliability of 99%, estimate the safety factor of the shaft at points B, C, and E.

Through load analysis, force and moment diagram are obtained, as shown below. Diagram below shows the intensity of the of axial force and torque alone the length of the shaft. (forces are in kN) (a) At point B, C, and E calculate the equivalent stresses in preparation for determining the fatigue safety factor. (b) For a reliability of 99%, estimate the safety factor of the shaft at points B, C, and E.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Concept explainers

Entropy

In physics, entropy means the amount of disorder or the degree of randomness associated with a thermodynamic system. The system is not self-organized when the entropy of the system is high. For instance, when a system is at an elevated temperature, its molecules are in random motion, vibrating and colliding with each other. During this scenario, the probability of finding a molecule at a particular place twice, is low. Under this circumstance, the system can be said to be in a high entropy.

Question

Please show every step to the solution. Write it neatly and clearly so that it is easy to follow. Thanks!

Through load analysis, force and moment diagram are obtained, as shown below. Diagram below shows
the intensity of the of axial force and torque alone the length of the shaft. (forces are in kN)
(a) At point B, C, and E calculate the equivalent stresses in preparation for determining the fatigue
safety factor.
(b) For a reliability of 99%, estimate the safety factor of the shaft at points B, C, and E.

The above left drawing shows a countershaft with helical gear B, bevel gear D, and two supporting
bearing A and C. Loads acting on the bevel gear are shown. Force on the helical gear can be determined
from equilibrium of moments about the shaft axis plus the given proportions of helical gear force
components. Shaft dimensions are given in the above right drawing. All shoulders fillets (at points where
diameter changes) have a radius of 5 mm. note that the shaft is designed so that only bearing A takes
thrust. The shaft is made of hardened steel, Su=1069 MPa, Sy=896MPA. All important surfaces are
finished by grinding. (Note: stress concentration)
В
Forces act at 500-mm dia.
D
F = 1.37 kN
A
В
550
F, = 5.33 kN
- 400
F; = 0.3675F,
F, = 0.2625F,
400
450
F = 1.37 kN
(1)
Forces act at 375-mm dia.
120 dia.
E
Кeyway
80 dia.

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