The balanced half-reaction occuring at the cathode in the redox reaction shown below is3MnOAlag) + 24Hiag) + 5Fe(s) → 3Mn + 5Fe + 12H20o(aq)(aq)F(ag)O Mn + 4H20o→ MnOala9) + 8Hao) + 5e-O MnO a(aq)+8H + 5e- → Mn? + 4H2O0(aq)(aq)+ Зе - Fe(s)O Fejag)O Fels) + Fe+ + 3e-(aq)

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The balanced half-reaction occuring at the cathode in the redox reaction shown below is + 5Fes) + 3Mn? + 5Fe + 12H2O0 (aq) 3Mnoalag) + 24Hao) (aq) O Mno + 4H2Ou→ Mnoalao) + 8Ha) + 5e (ag) O Mnoaloo) + 8Hao) + 5e¯ → Mn? + 4H200 n2+ (aq) + 4H2OW (aq) O Fela) 3+ + 3e + (aq) Fe(s) O Fe(s) 3+ + Зе → Feaq)

The balanced half-reaction occuring at the cathode in the redox reaction shown below is + 5Fes) + 3Mn? + 5Fe + 12H2O0 (aq) 3Mnoalag) + 24Hao) (aq) O Mno + 4H2Ou→ Mnoalao) + 8Ha) + 5e (ag) O Mnoaloo) + 8Hao) + 5e¯ → Mn? + 4H200 n2+ (aq) + 4H2OW (aq) O Fela) 3+ + 3e + (aq) Fe(s) O Fe(s) 3+ + Зе → Feaq)

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Electrolysis

Electrolysis is defined as the process of breaking down ionic compounds into their constituent elements by passing a direct electric current through the compound in a fluid state. The cathode reduces cations, while the anode oxidizes anions. An electrolyte, electrodes, and some form of external power source are the main components required for conducting electrolysis. A partition, such as an ion-exchange membrane or a salt bridge, may also be used, but this is optional. These are primarily used to prevent the products from diffusing near the opposing electrode.

Question

The balanced half-reaction occuring at the cathode in the redox reaction shown below is
3MnOAlag) + 24Hiag) + 5Fe(s) → 3Mn + 5Fe + 12H20o
(aq)
(aq)
F(ag)
O Mn + 4H20o→ MnOala9) + 8Hao) + 5e-
O MnO a(aq)
+8H + 5e- → Mn? + 4H2O0
(aq)
(aq)
+ Зе - Fe(s)
O Fejag)
O Fels) + Fe+ + 3e-
(aq)

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