(19) Consider the following redox reaction that occurs in a voltaic cell: Cr2+ (aq) + Cu2+ (aq) → Cr³+ (aq) + Cu+ (aq) If the cell is operating at 25°C, what is the value of the equilibrium constant (Kea)? (A) 1.41 x 10¹1 (B) 1.19 x 1018 (C) 5.53 x 105 (D) 2.79 x 1033 (E) 1.81 x 10-6

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**Problem (19): Equilibrium Constant Calculation for a Voltaic Cell**

Consider the following redox reaction that occurs in a voltaic cell:

\[ \text{Cr}^{2+} (\text{aq}) + \text{Cu}^{2+} (\text{aq}) \rightarrow \text{Cr}^{3+} (\text{aq}) + \text{Cu}^{+} (\text{aq}) \]

**Question:**  
If the cell is operating at 25°C, what is the value of the equilibrium constant (K_eq)?

**Options:**
- (A) \( 1.41 \times 10^{11} \)
- (B) \( 1.19 \times 10^{18} \)
- (C) \( 5.53 \times 10^{5} \)
- (D) \( 2.79 \times 10^{33} \)
- (E) \( 1.81 \times 10^{-6} \)

---

This problem requires an understanding of redox reactions and the calculation of equilibrium constants in electrochemical cells. The equilibrium constant, \( K_{eq} \), varies based on the Gibbs free energy change (ΔG°) for the reaction, which is linked to the cell potential (E°cell) by the following relationship:

\[ \Delta G° = -nFE°_{cell} \]

Where:
- \( \Delta G° \) is the standard Gibbs free energy change.
- \( n \) is the number of moles of electrons transferred in the reaction.
- \( F \) is the Faraday constant (\( 96,485 \, \text{C/mol} \)).
- \( E°_{cell} \) is the standard cell potential.

The relationship between the equilibrium constant \( K_{eq} \) and the Gibbs free energy is given by:

\[ \Delta G° = -RT \ln(K_{eq}) \]

Where:
- \( R \) is the universal gas constant (\( 8.314 \, \text{J/mol·K} \)).
- \( T \) is the temperature in Kelvin (\( 298 \, \text{K} \) for 25°C).

These equations allow for calculating \( K_{eq} \) based on \( E°_{cell} \). However, direct calculation isn't demonstrated here, the options listed are potential values of \(
Transcribed Image Text:**Problem (19): Equilibrium Constant Calculation for a Voltaic Cell** Consider the following redox reaction that occurs in a voltaic cell: \[ \text{Cr}^{2+} (\text{aq}) + \text{Cu}^{2+} (\text{aq}) \rightarrow \text{Cr}^{3+} (\text{aq}) + \text{Cu}^{+} (\text{aq}) \] **Question:** If the cell is operating at 25°C, what is the value of the equilibrium constant (K_eq)? **Options:** - (A) \( 1.41 \times 10^{11} \) - (B) \( 1.19 \times 10^{18} \) - (C) \( 5.53 \times 10^{5} \) - (D) \( 2.79 \times 10^{33} \) - (E) \( 1.81 \times 10^{-6} \) --- This problem requires an understanding of redox reactions and the calculation of equilibrium constants in electrochemical cells. The equilibrium constant, \( K_{eq} \), varies based on the Gibbs free energy change (ΔG°) for the reaction, which is linked to the cell potential (E°cell) by the following relationship: \[ \Delta G° = -nFE°_{cell} \] Where: - \( \Delta G° \) is the standard Gibbs free energy change. - \( n \) is the number of moles of electrons transferred in the reaction. - \( F \) is the Faraday constant (\( 96,485 \, \text{C/mol} \)). - \( E°_{cell} \) is the standard cell potential. The relationship between the equilibrium constant \( K_{eq} \) and the Gibbs free energy is given by: \[ \Delta G° = -RT \ln(K_{eq}) \] Where: - \( R \) is the universal gas constant (\( 8.314 \, \text{J/mol·K} \)). - \( T \) is the temperature in Kelvin (\( 298 \, \text{K} \) for 25°C). These equations allow for calculating \( K_{eq} \) based on \( E°_{cell} \). However, direct calculation isn't demonstrated here, the options listed are potential values of \(
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