The arrangement can also be represented as f(x) P1(x) *P2(x) g(x) Let us consider that P (x) = P1 (x) * P2 (x); Replace x with k and we get P (x) = [ [P1 (k) × P2 (x – k)] dk (1) The output can be calculated as g (x) = f (x) * P (x) : replace x with m, and we get g (x) = [ f (x – m) × P (m) dm . Plepoe , explaia.… (2) this step From equation (1) and (2), we get g (x) = f (x – m) x [S [P1 (k) × P2 (m – k)] dk] dm
The arrangement can also be represented as f(x) P1(x) *P2(x) g(x) Let us consider that P (x) = P1 (x) * P2 (x); Replace x with k and we get P (x) = [ [P1 (k) × P2 (x – k)] dk (1) The output can be calculated as g (x) = f (x) * P (x) : replace x with m, and we get g (x) = [ f (x – m) × P (m) dm . Plepoe , explaia.… (2) this step From equation (1) and (2), we get g (x) = f (x – m) x [S [P1 (k) × P2 (m – k)] dk] dm
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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