The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.941 g and a standard deviation of 0.328 g. The company that produces these cigarettes claims that it has now reduced the amount of nicotine. The supporting evidence consists of a sample of 35 cigarettes with a mean nicotine amount of 0.83 g.

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The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.941 g and a standard deviation of 0.328 g. The company that produces these cigarettes claims that it has now reduced the amount of nicotine. The supporting evidence consists of a sample of 35 cigarettes with a mean nicotine amount of 0.83 g.

Assuming that the given mean and standard deviation have NOT changed, find the probability of randomly seleting 35 cigarettes with a mean of 0.83 g or less.
P(M < 0.83 g) =
Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.

Based on the result above, is it valid to claim that the amoutn of nicotine is lower?

  • No. The probability of obtaining this data is high enough to have been a chance occurrence.
  • Yes. The probability of this data is unlikely to have occurred by chance alone.
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