The amounts of nicotine in a certain brand of cigarette are normally distributed with a mean of 0.919 g and a standard deviation of 0.325 g. The company that produces these cigarettes claims that it has now reduced the amount of nicotine. The supporting evidence consists of a sample of 39 cigarettes with a mean nicotine amount of 0.841 g. Assuming that the given mean and standard deviation have NOT changed, find the probability of randomly selecting 39 cigarettes with a mean of 0.841 g or less. P( ¯xx¯ < 0.841 g) = Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted. Based on the result above, is it valid to claim that the amount of nicotine is lower? Note: we say a result is unusual if the probability of the event occurring or a more extreme event occurring is less than 0.05 No. The probability of obtaining this data is high enough to have been a chance occurrence. Yes. The probability of this data is unlikely to have occurred by chance alone.
The amounts of nicotine in a certain brand of cigarette are
Assuming that the given mean and standard deviation have NOT changed, find the
P( ¯xx¯ < 0.841 g) =
Enter your answer as a number accurate to 4 decimal places. NOTE: Answers obtained using exact z-scores or z-scores rounded to 3 decimal places are accepted.
Based on the result above, is it valid to claim that the amount of nicotine is lower?
Note: we say a result is unusual if the probability of the
- No. The probability of obtaining this data is high enough to have been a chance occurrence.
- Yes. The probability of this data is unlikely to have occurred by chance alone.
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 13 images