Answered: Recently, the average price of a movie…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Question

Recently, the average price of a movie has been $7.90 in the U.S. It is known that ticket prices are normally distributed with a standard deviation of $1.43.

State the random variable.

xx = the average recent price of movie tickets in the U.S.
¯xx¯ = the recent price of a movie ticket in the U.S.
xx = the recent price of a movie ticket in the U.S.
¯xx¯ = the average recent price of movie tickets in the U.S.

Find the probability that the the recent price of a movie ticket in the U.S. is more than $8.25. Round to three decimal places.

Which is the notation for this probability?

P(¯xx¯ < 7.90)
P(xx > 8.25)
P(¯xx¯ > 7.90)
P(¯xx¯ > 8.25)
P(xx < 8.25)
P(xx < 7.90)

Find the probability that the average the recent price of a movie ticket of a random sample of 56 U.S. citizens is more than $8.25. Round to three decimal places.

Which is the notation for this probability?

P(xx > 8.25)
P(¯xx¯ > 8.25)
P(xx < 8.25)
P(¯xx¯ < 7.90)
P(xx < 7.90)
P(¯xx¯ > 7.90)

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Expert Solution