The Advanced Tech Company has a project to design an integrated information data base for a major bank. Data for the project are given in thefollowing table. Indirect project costs amount to $150 per day. The company will incur a $100 per day penalty for each day the project lasts beyondday 18.ActivityABCDEFGHNormalTime (days)54434b. What is the minimum-cost schedule?8001,0006001,2001,5001,300900500a. What is the project's duration if only normal times are used?The project duration is 22 day(s). (Enter your response as an integer.)2Normal Cost ($)55CrashTime (days)333N N22135Crash Cost($)1,6001,2009001,5001,7001,4001,200500Immediate Predecessor(s)With the minimum-cost schedule, the project duration is 17 day(s). (Enter your response as an integer.)c. What is the critical path for the minimum-cost schedule?The critical path for the minimum-cost schedule is B-D-E-G-HA, BBC, DEшоEG

Given data isThe network diagram of the given project data is shown below with the normal time of activities.The table below shows all the paths to complete the project with their normal duration. Path Calculation Duration A-C-E-F 5+4+4+2 15 11 A-C-E-G-H 5+4+4+5+5 23 14 B-C-E-F 4+4+4+2 14 10 B-C-E-G-H 4+4+4+5+5 22 13 B-D-E-F 4+3+4+2 13 9 B-D-E-G-H 4+3+4+5+5 21 12 So the critical path is A-C-E-G-H and the project duration is 23 days.The aim is to reduce to project duration to 18 days because only then the cost will be minimum as the penalty cost will be no more incurred. So the project duration can be shortened by crashing the critical activities. The table below shows the formulas used in excel for calculating slope. The calculated values are shown below. Now crashing begins with a critical activity that has the least slope. Activity H cannot be crashed because it has a slope value of 0. Crashing activity E Activity E will be crashed by 1 day and the project duration will become 22 days. With 22 days of duration, path B-C-E-G-H will also become a critical path. Crashing activity E Again activity E is the least slope activity and so it will be crashed by 1 day. It cannot be crashed any further now because it has a maximum crash limit of 2 days. Now the project duration is 21 days and so the path B-D-E-G-H is also a critical path. Crashing activity G Activity G is the next least slope activity with the aslope value of 150 so it will be crashed by 3 days directly because the duration of all other paths is not between 18 to 21 and the maximum crash limit of G is 3 days. Now the total time reduced in the project is 5 days and so the duration becomes 18 days. It is the minimum cost schedule because the penalty cost will not incur any more. Also, the project should not be crashed further because it will incur crash costs and so it will not be a minimum-cost schedule. Hence, with the minimum cost schedule, the project duration is 18 days.The minimum cost schedule is shown below. Here direct or indirect costs are not presented in the table because they will remain as it is and the cost can be minimized by reducing penalty cost and crash cost. The critical path of minimum-cost schedule is B-D-E-G-H.