The addition of 3.15 g of Ba(OH)2-8H20 to a solution of 1.52 g of NHASCN in 100 g of water in a calorimeter caused the temperature to fall by 3.1 °C. Assuming the specific heat of the solution and products is 4.20 J/g °C, calculate the approximate amount of heat absorbed by the reaction (in KJ), which can be represented by the following equation: Ba(OH)2-8H2O(s) + 2NH¼SCN(aq) –→ Ba(SCN)2(aq) + 2NH3(aq) + 10H2O() Type your answer.. Previous Next

Chemistry
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The addition of 3.15 g of Ba(OH)2 8H2O to a solution of 1.52 g of NHĄSCN in 100 g of water in a calorimeter caused the temperature to fall by 3.1 °C. Assuming the specific heat
of the solution and products is 4.20 J/g °C, calculate the approximate amount of heat absorbed by the reaction (in KJ), which can be represented by the following equation:
Ba(OH)2-8H2O(s) + 2NH¼SCN(aq) –→ Ba(SCN)2(aq) + 2NH3(aq) + 10H2O(1)
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Transcribed Image Text:The addition of 3.15 g of Ba(OH)2 8H2O to a solution of 1.52 g of NHĄSCN in 100 g of water in a calorimeter caused the temperature to fall by 3.1 °C. Assuming the specific heat of the solution and products is 4.20 J/g °C, calculate the approximate amount of heat absorbed by the reaction (in KJ), which can be represented by the following equation: Ba(OH)2-8H2O(s) + 2NH¼SCN(aq) –→ Ba(SCN)2(aq) + 2NH3(aq) + 10H2O(1) 1 Type your answer. 2 Previous Next 3 4
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