Calculate the molar enthalpy for dissolving 25 g of NaCl in 100g of water inside a calorimeter. The calorimeter heat capacity is 500 J/c. The initial temperature is 25C and the final temperature is 26.5 C
Calculate the molar enthalpy for dissolving 25 g of NaCl in 100g of water inside a calorimeter. The calorimeter heat capacity is 500 J/c. The initial temperature is 25C and the final temperature is 26.5 C
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Transcribed Image Text:**Problem Statement:**
Calculate the molar enthalpy for dissolving 25 g of NaCl in 100 g of water inside a calorimeter. The calorimeter heat capacity is 500 J/°C. The initial temperature is 25°C and the final temperature is 26.5°C.
**Explanation:**
To solve this problem, one must use the formula for heat transfer in a calorimeter:
Q = (C_calorimeter + m_water * c_water) * ΔT
Where:
- Q is the heat absorbed or released (in Joules).
- C_calorimeter is the heat capacity of the calorimeter (500 J/°C).
- m_water is the mass of the water (100 g).
- c_water is the specific heat capacity of water (4.18 J/g°C, commonly used value).
- ΔT is the change in temperature (final temperature - initial temperature).
The molar enthalpy (ΔH) can be calculated by relating Q to the moles of NaCl dissolved:
ΔH = -Q / n
Where n is the number of moles of NaCl. Calculate n using NaCl's molar mass (58.44 g/mol).
Expert Solution

Step 1
Given:
The mass of NaCl = 25 g
The mass of water taken = 100 g
The calorimeter heat capacity = 500 J/oC
The initial temperature = 25 oC
The final temperature = 26.5 oC
We have to calculate the molar enthalpy change.
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