A generic solid, X, has a molar mass of 83.3 g/mol. In a constant-pressure calorimeter, 17.2 g of X is dissolved in 219 g of water at 23.00 °C. X(s) X(aq) The temperature of the resulting solution rises to 27.00 °C. Assume the solution has the same specific heat as water, 4.184 J/(g-°C), and that there is negligible heat loss to the surroundings. How much heat was absorbed by the solution? 3.953 x103 q = kJ Incorrect What is the enthalpy of the reaction? AHrxn kJ/mol Incorrect
A generic solid, X, has a molar mass of 83.3 g/mol. In a constant-pressure calorimeter, 17.2 g of X is dissolved in 219 g of water at 23.00 °C. X(s) X(aq) The temperature of the resulting solution rises to 27.00 °C. Assume the solution has the same specific heat as water, 4.184 J/(g-°C), and that there is negligible heat loss to the surroundings. How much heat was absorbed by the solution? 3.953 x103 q = kJ Incorrect What is the enthalpy of the reaction? AHrxn kJ/mol Incorrect
Chemistry
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How much heat was absorbed by the solution?
What is the enthalpy of the reaction?
![A generic solid, X, has a molar mass of 83.3 g/mol. In a constant-pressure calorimeter, 17.2 g of X is dissolved in 219 g of water at 23.00 °C.
\[ \text{X(s)} \rightarrow \text{X(aq)} \]
The temperature of the resulting solution rises to 27.00 °C. Assume the solution has the same specific heat as water, 4.184 J/(g·°C), and that there is negligible heat loss to the surroundings.
**How much heat was absorbed by the solution?**
\[ q = \]
- The given answer is \( 3.953 \times 10^3 \) kJ (Incorrect).
**What is the enthalpy of the reaction?**
\[ \Delta H_{\text{rxn}} = \]
- This answer is required in kJ/mol (Incorrect).
*Explanation:*
- **Calculation of q (heat absorbed):** The question asks for the heat absorbed by the solution, which is typically calculated using the formula:
\[ q = m \cdot c \cdot \Delta T \]
where \( m \) is the mass, \( c \) is the specific heat, and \( \Delta T \) is the change in temperature.
- **Enthalpy of reaction calculation:** The enthalpy change of the reaction, \( \Delta H_{\text{rxn}} \), involves using the heat absorbed and considering the moles of substance involved in the reaction for a molar perspective.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb1d14486-aab8-45fa-9185-3d15b7af8b4b%2Fb845f9ec-1329-4ea5-8d3c-694f54f95a10%2Fc41hm7i_processed.png&w=3840&q=75)
Transcribed Image Text:A generic solid, X, has a molar mass of 83.3 g/mol. In a constant-pressure calorimeter, 17.2 g of X is dissolved in 219 g of water at 23.00 °C.
\[ \text{X(s)} \rightarrow \text{X(aq)} \]
The temperature of the resulting solution rises to 27.00 °C. Assume the solution has the same specific heat as water, 4.184 J/(g·°C), and that there is negligible heat loss to the surroundings.
**How much heat was absorbed by the solution?**
\[ q = \]
- The given answer is \( 3.953 \times 10^3 \) kJ (Incorrect).
**What is the enthalpy of the reaction?**
\[ \Delta H_{\text{rxn}} = \]
- This answer is required in kJ/mol (Incorrect).
*Explanation:*
- **Calculation of q (heat absorbed):** The question asks for the heat absorbed by the solution, which is typically calculated using the formula:
\[ q = m \cdot c \cdot \Delta T \]
where \( m \) is the mass, \( c \) is the specific heat, and \( \Delta T \) is the change in temperature.
- **Enthalpy of reaction calculation:** The enthalpy change of the reaction, \( \Delta H_{\text{rxn}} \), involves using the heat absorbed and considering the moles of substance involved in the reaction for a molar perspective.
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