A generic solid, X, has a molar mass of 83.3 g/mol. In a constant-pressure calorimeter, 17.2 g of X is dissolved in 219 g of water at 23.00 °C. X(s) X(aq) The temperature of the resulting solution rises to 27.00 °C. Assume the solution has the same specific heat as water, 4.184 J/(g-°C), and that there is negligible heat loss to the surroundings. How much heat was absorbed by the solution? 3.953 x103 q = kJ Incorrect What is the enthalpy of the reaction? AHrxn kJ/mol Incorrect

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How much heat was absorbed by the solution?

What is the enthalpy of the reaction?
A generic solid, X, has a molar mass of 83.3 g/mol. In a constant-pressure calorimeter, 17.2 g of X is dissolved in 219 g of water at 23.00 °C.

\[ \text{X(s)} \rightarrow \text{X(aq)} \]

The temperature of the resulting solution rises to 27.00 °C. Assume the solution has the same specific heat as water, 4.184 J/(g·°C), and that there is negligible heat loss to the surroundings.

**How much heat was absorbed by the solution?**

\[ q = \]

- The given answer is \( 3.953 \times 10^3 \) kJ (Incorrect).

**What is the enthalpy of the reaction?**

\[ \Delta H_{\text{rxn}} = \]

- This answer is required in kJ/mol (Incorrect).

*Explanation:*

- **Calculation of q (heat absorbed):** The question asks for the heat absorbed by the solution, which is typically calculated using the formula:
  \[ q = m \cdot c \cdot \Delta T \]
  where \( m \) is the mass, \( c \) is the specific heat, and \( \Delta T \) is the change in temperature.
  
- **Enthalpy of reaction calculation:** The enthalpy change of the reaction, \( \Delta H_{\text{rxn}} \), involves using the heat absorbed and considering the moles of substance involved in the reaction for a molar perspective.
Transcribed Image Text:A generic solid, X, has a molar mass of 83.3 g/mol. In a constant-pressure calorimeter, 17.2 g of X is dissolved in 219 g of water at 23.00 °C. \[ \text{X(s)} \rightarrow \text{X(aq)} \] The temperature of the resulting solution rises to 27.00 °C. Assume the solution has the same specific heat as water, 4.184 J/(g·°C), and that there is negligible heat loss to the surroundings. **How much heat was absorbed by the solution?** \[ q = \] - The given answer is \( 3.953 \times 10^3 \) kJ (Incorrect). **What is the enthalpy of the reaction?** \[ \Delta H_{\text{rxn}} = \] - This answer is required in kJ/mol (Incorrect). *Explanation:* - **Calculation of q (heat absorbed):** The question asks for the heat absorbed by the solution, which is typically calculated using the formula: \[ q = m \cdot c \cdot \Delta T \] where \( m \) is the mass, \( c \) is the specific heat, and \( \Delta T \) is the change in temperature. - **Enthalpy of reaction calculation:** The enthalpy change of the reaction, \( \Delta H_{\text{rxn}} \), involves using the heat absorbed and considering the moles of substance involved in the reaction for a molar perspective.
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