The A and B alleles are codominant, and the O allele is recessive. An AB blood type mother has children with a B blood type father (genotype BO). What are the chances that their offspring will have AB-type blood? Express in percentage.

The A and B alleles are codominant, and the O allele is recessive. An AB blood type mother has children with a B blood type father (genotype BO). What are the chances that their offspring will have AB-type blood? Express in percentage.

Name: The A and B alleles are codominant, and the O allele is recessive. An
Uploaded: 2024-03-20T06:42:55.000Z
Channel: Bartleby
Description: The A and B alleles are codominant, and the O allele is recessive. An AB blood type mother has children with a B blood type father (genotype BO). What are the chances that their offspring will have AB-type blood? Express in percentage.

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter6: Cytogenetics: Karyotypes And Chromosome Aberrations

Section: Chapter Questions

Problem 2QP: Given the karyotype shown at right, is this a male or a female? Normal or abnormal? What would the...

See similar textbooks

Similar questions

Could an individual with blood type O (genotype ii) be a legitimate child of parents in which one parent had blood type A and the other parent had blood type B?
Several genes in humans in addition to the ABO gene(I) give rise to recognizable antigens on the surface ofred blood cells. The MN and Rh genes are two examples. The Rh locus can contain either a positive or anegative allele, with positive being dominant to negative. M and N are codominant alleles of the MN gene.The following chart shows several mothers and theirchildren. For each mother-child pair, choose the fatherof the child from among the males in the right column, assuming one child per male.Mother Child Malesa. O M Rh(pos) B MN Rh(neg) O M Rh(neg)b. B MN Rh(neg) O N Rh(neg) A M Rh(pos)c. O M Rh(pos) A M Rh(neg) O MN Rh(pos)d. AB N Rh(neg) B MN Rh(neg) B MN Rh(pos)
A light-haired man has blood type O, his wife has dark hair and blood type AB, but her father had light hair. Assume dark hair (H) is dominant to light (h). What is the probability they will have a child with dark hair and blood type A? What is the probability they will have a child with light hair and blood type B? What is the total number of phenotypes their children could show?
The father of two children is type O+, and the mother is type A+. The children are O- and A+. Given this information, what are the genotypes of the father vs. the mother at both the “I” and “Rh” alleles? Explain your rationale.
If I got an A from my father and a O from my mother for my genotype. How would my phenotype be expressed? What is my blood type? Explain your reasoning for both answers.
Cystic fibrosis (CF) is an autosomal recessive trait. A three-generation pedigree is shown below for a family that carries the mutant allele for cystic fibrosis. Note that carriers are not colored in to allow you to figure out their genotypes. Normal allele = F CF mutant allele = f What is the genotype of individual #13? A) ff B) FF C) Ff D) it is impossible to tell
For an individual expressing the dominant phenotype, explain why you must list two possible genotypes.
Duchenne’s muscular dystrophy (DMD) is an X-linked disease that causes progressive muscle weakness and is often fatal. “XD” represents the wild type allele, and “Xd,” the mutant allele. Jonah is XDXd Y and his brother Pete is Xd Y. Jonah and Pete BOTH have DMD of equal severity and phenotypes. You might have thought Jonah’s DMD would be less severe given his genotype. To better understand the situation, you investigate Jonah’s Xist chromosome region in his defective muscle cells. Which of the following is consistent with his phenotype? (Select all that apply.) The Xd-containing chromosome is inactive in defective muscle cells. The XD-containing chromosome has a methylated Xist promoter. The XD-containing chromosome has an unmethylated Xist promoter. The Xd-containing chromosome is active in defective muscle cells.
Joanne has AB blood and Henry has AB blood. They have one child with A blood, one child with AB blood, and another child that has O Bombay phenotype blood. Please explain what is happening here. What is the chance that Joanne and Henry will have a child with B blood type? What is the name of the phenomenon that is responsible for the Bombay phenotype?
The gene for polydactyly (P) is autosomal and dominant to normal fingers (p). Hemophilia is sex-linked and recessive (X h ). A man and his wife both of whom are polydactylous and have normal red blood cells have a child who is non-polydactylous and with hemophilia. What are their genotypes?
A mother is heterozygous for the X-linked gene for colorblindness and also heterozygous for the autosomal inherited sickle cell anemia. She is married to a man who can see color normally and who is heterozygous for sickle cell trait. Using b (colorblind), B (normal color), S (normal hemoglobin), s (sickle cell), answer the following: a. What are the genotypes of the parents? b: What is the probability of having a child who is both color blind and has sickle cell anemia?
4:33 4 Alger Edit Today 4:31 PM O LIVE Which of the following statements regarding Mendel's observations and Laws are still true and part of our knowledge of genetics today? (Check all that true.) M Two alleles segregate during meiosis, ending up in different gametes. Each pea plant has 2 alleles for every gene, but only contributes one in each gamete. The recombination of alleles in a zygote is completely random. The Law of Independeht Assortment was determined by following three traits in pea plants, TMendle was able to determine his Law of Segregation by following ane trait in pea plants. Every offspring inherits only 1 allele from each parent.