The 3-winding single-phase transformer of Fig. 8.1 is rated at 13.8 kV/138kV/4.157 kV and 50 MVA/40 MVA/10 MVA. Terminations are as followings: 13.8 kV winding: 138 kV winding: 4.157 kV winding: 5 MVA load, pf 0.866 leading 13.8 kV Source 35 MVA load, pf = 0.866 lagging Using Spase = 10 MVA, and voltage ratings as bases, (a) Draw the pu equivalent circuit. (b) Solve for the primary current, power, and power, and power factor.

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Example 2:
The 3-winding single-phase transformer of Fig. 8.1 is rated at 13.8 kV/138kV/4.157 kV and 50 MVA/40
MVA/10 MVA. Terminations are as followings:
13.8 kV winding:
138 kV winding:
4.157 kV winding: 5 MVA load, pf = 0.866 leading
13.8 kV Source
35 MVA load, pf = 0.866 lagging
Using Suse= 10 MVA, and voltage ratings as bases,
(a) Draw the pu equivalent circuit.
(b) Solve for the primary current, power, and power, and power factor.
N,N, N,
ideal
Transcribed Image Text:Example 2: The 3-winding single-phase transformer of Fig. 8.1 is rated at 13.8 kV/138kV/4.157 kV and 50 MVA/40 MVA/10 MVA. Terminations are as followings: 13.8 kV winding: 138 kV winding: 4.157 kV winding: 5 MVA load, pf = 0.866 leading 13.8 kV Source 35 MVA load, pf = 0.866 lagging Using Suse= 10 MVA, and voltage ratings as bases, (a) Draw the pu equivalent circuit. (b) Solve for the primary current, power, and power, and power factor. N,N, N, ideal
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