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The 200-kg snowmobile with passenger is traveling down the hill such that when it is at point A, it is traveling at 4 m/s and increasing its speed at 2 m/s². Determine the resultant normal force and the resultant frictional force exerted on the tracks at this instant. Neglect the size of the snowmobile. 10 m- 5 m X -y = -5(10-³)x³ Ans. NA 924.8 N = fA= 1232 N (Directed opposite the direction of travel for the snowmobile)

The 200-kg snowmobile with passenger is traveling down the hill such that when it is at point A, it is traveling at 4 m/s and increasing its speed at 2 m/s². Determine the resultant normal force and the resultant frictional force exerted on the tracks at this instant. Neglect the size of the snowmobile. 10 m- 5 m X -y = -5(10-³)x³ Ans. NA 924.8 N = fA= 1232 N (Directed opposite the direction of travel for the snowmobile)

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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3.) The 200-kg snowmobile with passenger is traveling down the hill such that when it is at point A, it is traveling at 4 m/s and increasing its speed at 2 m/s². Determine the resultant normal force and the resultant frictional force exerted on the tracks at this instant. Neglect the size of the snowmobile. 10 m 5m x -y = -5(10-3)x³ Ans. NA 924.8 N fA= 1232 N (Directed opposite the direction of travel for the snowmobile)
Transcribed Image Text:3.) The 200-kg snowmobile with passenger is traveling down the hill such that when it is at point A, it is traveling at 4 m/s and increasing its speed at 2 m/s². Determine the resultant normal force and the resultant frictional force exerted on the tracks at this instant. Neglect the size of the snowmobile. 10 m 5m x -y = -5(10-3)x³ Ans. NA 924.8 N fA= 1232 N (Directed opposite the direction of travel for the snowmobile)
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