TEST YOUR UNDERSTANDING! A rectangular block is subjected to a triaxial loading consisting of three uniformly distributed forces as shown. If v = 0.3 and E= 0.5 GPa, compute the change in volume of the block. The length of side along x is 3 m, side along y is 4 m and side along the z-axis is 5 m. Also, determine a single distributed loading in the x-direction that will produce the same z deformation as the original loading. Note that there is another P₂ applied at the back for equilibrium in the original loading shown. Px=200 kN Pz 220 kN Py=160 kN Py=160 kN (TYU 2-3) Px 200 kN Answer to Test your understanding box change in volume = 9.1208 x 104 m³ (decrease); single equivalent force along x = 1208.8889 KN, T
TEST YOUR UNDERSTANDING! A rectangular block is subjected to a triaxial loading consisting of three uniformly distributed forces as shown. If v = 0.3 and E= 0.5 GPa, compute the change in volume of the block. The length of side along x is 3 m, side along y is 4 m and side along the z-axis is 5 m. Also, determine a single distributed loading in the x-direction that will produce the same z deformation as the original loading. Note that there is another P₂ applied at the back for equilibrium in the original loading shown. Px=200 kN Pz 220 kN Py=160 kN Py=160 kN (TYU 2-3) Px 200 kN Answer to Test your understanding box change in volume = 9.1208 x 104 m³ (decrease); single equivalent force along x = 1208.8889 KN, T
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Transcribed Image Text:TEST YOUR UNDERSTANDING!
A rectangular block is subjected to a triaxial loading
consisting of three uniformly distributed forces as
shown. If v = 0.3 and E= 0.5 GPa, compute the change
in volume of the block. The length of side along x is 3 m,
side along y is 4 m and side along the z-axis is 5 m. Also,
determine a single distributed loading in the x-direction
that will produce the same z deformation as the original
loading. Note that there is another Pz applied at the back
for equilibrium in the original loading shown.
Px=200 kN
Pz-220 kN
Py=160 kN
Py=160 kN
(TYU 2-3)
Px=200 kN
Answer to Test your understanding box
change in volume = 9.1208 x 104 m³ (decrease); single equivalent force along x = 1208.8889 kN, T
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