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Task 2: Comparable Interface and Record (10 Points) 1. You are tasked with creating a Java record of Dog (UML is shown below). The dog record should include the dog's name, breed, age, and weight. You are required to implement the Comparable interface for the Dog record so that you can sort the records based on the dogs' ages. Create a Java record named Dog.java. name: String breed: String age: int weight: double + toString(): String <> Dog + compareTo(otherDog: Dog): int <> Comparable 2. In the Dog record, establish a main method and proceed to generate an array named dogList containing three Dog objects, each with the following attributes: Dog1: name: "Buddy", breed: "Labrador Retriever", age: 5, weight: 25.5 Dog2: name: "Max", breed: "Golden Retriever", age: 3, weight: 30 Dog3: name: "Charlie", breed: "German Shepherd", age: 2, weight: 22 3. Print the dogs in dogList before sorting the dogList by age. (Please check the example output for the format). • 4. Sort the dogList using Arrays.sort(). 5. Print the dogs in dogList after sorting. Note: 1. Implement the Comparable interface for the Dog record so that dogs can be compared based on their ages. The compareTo() method should compare dogs based on their ages in ascending order. 2. Use Arrays.toString() to print the array of Dogs. 3. Use Arrays.sort() to sort the dogList array. 4. Override the toString() method in the Dog record to print the three dogs in the example format: Example: Before sorting: [Dog: age=5, Dog: age=3, Dog: age=2] After sorting: [Dog: age=2, Dog: age=3, Dog: age=5]

Task 2: Comparable Interface and Record (10 Points) 1. You are tasked with creating a Java record of Dog (UML is shown below). The dog record should include the dog's name, breed, age, and weight. You are required to implement the Comparable interface for the Dog record so that you can sort the records based on the dogs' ages. Create a Java record named Dog.java. name: String breed: String age: int weight: double + toString(): String <> Dog + compareTo(otherDog: Dog): int <> Comparable 2. In the Dog record, establish a main method and proceed to generate an array named dogList containing three Dog objects, each with the following attributes: Dog1: name: "Buddy", breed: "Labrador Retriever", age: 5, weight: 25.5 Dog2: name: "Max", breed: "Golden Retriever", age: 3, weight: 30 Dog3: name: "Charlie", breed: "German Shepherd", age: 2, weight: 22 3. Print the dogs in dogList before sorting the dogList by age. (Please check the example output for the format). • 4. Sort the dogList using Arrays.sort(). 5. Print the dogs in dogList after sorting. Note: 1. Implement the Comparable interface for the Dog record so that dogs can be compared based on their ages. The compareTo() method should compare dogs based on their ages in ascending order. 2. Use Arrays.toString() to print the array of Dogs. 3. Use Arrays.sort() to sort the dogList array. 4. Override the toString() method in the Dog record to print the three dogs in the example format: Example: Before sorting: [Dog: age=5, Dog: age=3, Dog: age=2] After sorting: [Dog: age=2, Dog: age=3, Dog: age=5]

EBK JAVA PROGRAMMING
EBK JAVA PROGRAMMING
9th Edition
ISBN:9781337671385
Author:FARRELL
Publisher:FARRELL
Chapter10: Introduction To Inheritance
Section: Chapter Questions
Problem 14RQ
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Task 2: Comparable Interface and Record (10 Points) 1. You are tasked with creating a Java record of Dog (UML is shown below). The dog record should include the dog's name, breed, age, and weight. You are required to implement the Comparable interface for the Dog record so that you can sort the records based on the dogs' ages. Create a Java record named Dog.java. name: String breed: String age: int weight: double + toString(): String <<Record>> Dog + compareTo(otherDog: Dog): int <<interface>> Comparable<Dog> 2. In the Dog record, establish a main method and proceed to generate an array named dogList containing three Dog objects, each with the following attributes: Dog1: name: "Buddy", breed: "Labrador Retriever", age: 5, weight: 25.5 Dog2: name: "Max", breed: "Golden Retriever", age: 3, weight: 30 Dog3: name: "Charlie", breed: "German Shepherd", age: 2, weight: 22 3. Print the dogs in dogList before sorting the dogList by age. (Please check the example output for the format). • 4. Sort the dogList using Arrays.sort(). 5. Print the dogs in dogList after sorting. Note:
Transcribed Image Text:Task 2: Comparable Interface and Record (10 Points) 1. You are tasked with creating a Java record of Dog (UML is shown below). The dog record should include the dog's name, breed, age, and weight. You are required to implement the Comparable interface for the Dog record so that you can sort the records based on the dogs' ages. Create a Java record named Dog.java. name: String breed: String age: int weight: double + toString(): String <<Record>> Dog + compareTo(otherDog: Dog): int <<interface>> Comparable<Dog> 2. In the Dog record, establish a main method and proceed to generate an array named dogList containing three Dog objects, each with the following attributes: Dog1: name: "Buddy", breed: "Labrador Retriever", age: 5, weight: 25.5 Dog2: name: "Max", breed: "Golden Retriever", age: 3, weight: 30 Dog3: name: "Charlie", breed: "German Shepherd", age: 2, weight: 22 3. Print the dogs in dogList before sorting the dogList by age. (Please check the example output for the format). • 4. Sort the dogList using Arrays.sort(). 5. Print the dogs in dogList after sorting. Note:
1. Implement the Comparable interface for the Dog record so that dogs can be compared based on their ages. The compareTo() method should compare dogs based on their ages in ascending order. 2. Use Arrays.toString() to print the array of Dogs. 3. Use Arrays.sort() to sort the dogList array. 4. Override the toString() method in the Dog record to print the three dogs in the example format: Example: Before sorting: [Dog: age=5, Dog: age=3, Dog: age=2] After sorting: [Dog: age=2, Dog: age=3, Dog: age=5]
Transcribed Image Text:1. Implement the Comparable interface for the Dog record so that dogs can be compared based on their ages. The compareTo() method should compare dogs based on their ages in ascending order. 2. Use Arrays.toString() to print the array of Dogs. 3. Use Arrays.sort() to sort the dogList array. 4. Override the toString() method in the Dog record to print the three dogs in the example format: Example: Before sorting: [Dog: age=5, Dog: age=3, Dog: age=2] After sorting: [Dog: age=2, Dog: age=3, Dog: age=5]
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