Table 1: Estimation of Dissolved Oxygen: SI No Volume of water Initial sample (ml) burette Final burette Volume of NazS203 reading (ml) reading (ml) consumed (V2 ml) 100.0 0.0 7.4 7.4 1 100.0 7.4 14.8 7.4 2 100.0 14.8 22.1 7.3 3 Calculations: Normality of water sample: N¡V1(water sample) =N2V2(Na2S2O3) x74 N2 xV2 N1 = vi 40 1.85 x 10-3 100 N1 = 1.85 x 10-3 • Amount of Dissolved oxygen in water sample: Amount of Dissolved oxygen in water sample = N1 x equivalent weight of oxygen = 1.85 x 10-3 x 8 g/L 3D 1.85 х 10-3 х 8х 103 рpm = 14.8 PPM Amount of Dissolved oxygen in water sample = 14.8 PPM

Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter10: Solutions
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Problem 89QAP
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EXPERIMENT :Estimation of Dissolved Oxygen

I want Result & Analysis for this experiment includes Precautions

Observations:
Table 1: Estimation of Dissolved Oxygen:
SINO Volume of water Initial
sample (ml)
burette Final
burette Volume
of
NazS203
reading (ml)
reading (ml)
consumed (V2 ml)
100.0
0.0
7.4
7.4
1
100.0
7.4
14.8
7.4
2
100.0
14.8
22.1
7.3
3
Calculations:
Normality of water sample:
N¡Vi(water sample) =N2V2(Na2S203)
x 7.4
1.85 x 10-3
N2 XV2
N1 =
40
v1
100
N1 = 1.85 x 10-3
• Amount of Dissolved oxygen in water sample:
Amount of Dissolved oxygen in water sample = N1 x equivalent weight of oxygen
= 1.85 × 10-3 × 8 g/L
= 1.85 x 10-3 × 8 × 103 ppm
= 14.8 PPM
Amount of Dissolved oxygen in water sample = 14.8 PPM
Transcribed Image Text:Observations: Table 1: Estimation of Dissolved Oxygen: SINO Volume of water Initial sample (ml) burette Final burette Volume of NazS203 reading (ml) reading (ml) consumed (V2 ml) 100.0 0.0 7.4 7.4 1 100.0 7.4 14.8 7.4 2 100.0 14.8 22.1 7.3 3 Calculations: Normality of water sample: N¡Vi(water sample) =N2V2(Na2S203) x 7.4 1.85 x 10-3 N2 XV2 N1 = 40 v1 100 N1 = 1.85 x 10-3 • Amount of Dissolved oxygen in water sample: Amount of Dissolved oxygen in water sample = N1 x equivalent weight of oxygen = 1.85 × 10-3 × 8 g/L = 1.85 x 10-3 × 8 × 103 ppm = 14.8 PPM Amount of Dissolved oxygen in water sample = 14.8 PPM
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