T) of 313 degree Kelvin with a pressure (P) of 65 kPa using Bisection Method for Pc = 4.6 Pa, Tc = 191 degree Kelvin and the universal gas constant (R) of 0.518 kJ/kg °K. Compute and complete the tabulated solution. Terminate if Ea s 0.00001. (Hint: Substitute values and heglect the units. Solve variables a and b first then use it in the function) RT P = Tc b = 0.0866 R Pc R?Tc2.5 a a = 0.427 (v – b) v(v+ b)\T Pc
T) of 313 degree Kelvin with a pressure (P) of 65 kPa using Bisection Method for Pc = 4.6 Pa, Tc = 191 degree Kelvin and the universal gas constant (R) of 0.518 kJ/kg °K. Compute and complete the tabulated solution. Terminate if Ea s 0.00001. (Hint: Substitute values and heglect the units. Solve variables a and b first then use it in the function) RT P = Tc b = 0.0866 R Pc R?Tc2.5 a a = 0.427 (v – b) v(v+ b)\T Pc
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Transcribed Image Text:The Redlich – Kwong is given below. Determine the volume in a 3m³ tank at a temperature
(T) of 313 degree Kelvin with a pressure (P) of 65 kPa using Bisection Method for Pc = 4.6
kPa, Tc = 191 degree Kelvin and the universal gas constant (R) of 0.518 kJ/kg °K. Compute
and complete the tabulated solution. Terminate if Ea <0.00001. (Hint: Substitute values and
neglect the units. Solve variables a and b first then use it in the function)
R?Tc2.5
RT
P =
(v – b) v(v+ b)VT
Tc
= 0.0866 R
Pc
a
b
a = 0.427
Pc
Vo
V2
V,
f(V2)
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