Which equation for the Nusselt number should be used for a forced convection process in a pipe where the calculated value of the Prandtl's number is 4.500 and the Reynold's number is 100,000, 0.62 Reß Pra Rep = 0.3 + a. [1+ (0.4/Pr)*9j4 282,000 Nup = 1.86 b. LS6( D (2 Rep Pr) Nup = 0.027 Ref* Pr H4 C. (f/2)(Rep – 1000)(Pr) K 1+ 12.7(f/2)² (Pr0 – 1) Nup =
Which equation for the Nusselt number should be used for a forced convection process in a pipe where the calculated value of the Prandtl's number is 4.500 and the Reynold's number is 100,000, 0.62 Reß Pra Rep = 0.3 + a. [1+ (0.4/Pr)*9j4 282,000 Nup = 1.86 b. LS6( D (2 Rep Pr) Nup = 0.027 Ref* Pr H4 C. (f/2)(Rep – 1000)(Pr) K 1+ 12.7(f/2)² (Pr0 – 1) Nup =
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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
Transcribed Image Text:Which equation for the Nusselt number should be used for a forced convection process in a pipe where the calculated value of the
Prandtl's number is 4.500 and the Reynold's number is 100,000.
0.62 Re Pra
Rep
45
Nup = 0.3 +
[1+ (0.4/Pr)aju41+(
13
282,000
a.
0.14
Nup = 1.86 Rep Pr
b.
Nup = 0.027 Ret Prle H 0.14
C.
(f/2)(Rep- 1000)(Pr)
K
Nup =
d.
1+ 12.7(f/2) (Prs – 1)
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