What constant (use the letter in your answer) does the Sherwood number have in it's definition that we need in order to perform mass transfer calculations? ANS:_________. This simplification is necessary because so many phenomena can be affecting the mass transfer at once such as geometry or convection or even temperature gradients. Basically someone else has already solved those simultaneous differential equations for that particular situation and in our practice we can use their correlation rather than rework all those details ourselves.

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