Systolic Blood Pressure Assume that the mean systolic blood pressure of normal adults is 120 millimeters of mercury (mmHg) and the standard deviation is 5.6. Assume the variable is normally distributed. Round the answers to at least 4 decimal places and intermediate z-value calculations to 2 decimal places. Part 1 of 3 If an individual is selected, find the probability that the individual's pressure will be between 120 and 122.6 mmHg. P(120 < X< 122.6) = 0.1772 Part: 1 / 3 Part 2 of 3 If a sample of 29 adults is randomly selected, find the probability that the sample mean will be between 120 and 122.6 mmHg. Assume that the sample is taken from a large population and the correction factor can be ignored. P(120 < X < 122.6) = X

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Systolic Blood Pressure Assume that the mean systolic blood pressure of normal adults is 120 millimeters of mercury (mmHg) and the standard deviation is
5.6. Assume the variable is normally distributed. Round the answers to at least 4 decimal places and intermediate z-value calculations to 2 decimal places.
Part 1 of 3
If an individual is selected, find the probability that the individual's pressure will be between 120 and 122.6 mmHg.
P(120 < X < 122.6) = 0.1772
Part: 1 / 3
Part 2 of 3
If a sample of 29 adults is randomly selected, find the probability that the sample mean will be between 120 and 122.6 mmHg. Assume that the sample is
taken from a large population and the correction factor can be ignored.
P(120 < X < 122.6)
=
X
Transcribed Image Text:Systolic Blood Pressure Assume that the mean systolic blood pressure of normal adults is 120 millimeters of mercury (mmHg) and the standard deviation is 5.6. Assume the variable is normally distributed. Round the answers to at least 4 decimal places and intermediate z-value calculations to 2 decimal places. Part 1 of 3 If an individual is selected, find the probability that the individual's pressure will be between 120 and 122.6 mmHg. P(120 < X < 122.6) = 0.1772 Part: 1 / 3 Part 2 of 3 If a sample of 29 adults is randomly selected, find the probability that the sample mean will be between 120 and 122.6 mmHg. Assume that the sample is taken from a large population and the correction factor can be ignored. P(120 < X < 122.6) = X
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Step 1: Provide the given information

Suppose the random variable x defines the systolic blood pressure of normal adults.

It is given that; x follows normal distribution with mean of italic µ space equals space 120 mmHg and the standard deviation of space sigma space equals space 5.6 spacemmHg.

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