Assume the heights of women are normally distributed with a mean of 67.5 inches and a standard deviation of 2.5 inches. If 25 women are randomly selected, find the probability that they have a mean height greàter than 68 inches. Draw a bell curve, label your mean and shade the area that you are trying to find. Then answer the question. (round to 4 decimal places) Before you solve the problem answer the following questions:

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**Educational Content: Understanding Probability with Normal Distribution**

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**Problem Statement:**

Assume the heights of women are normally distributed with a mean of 67.5 inches and a standard deviation of 2.5 inches. If 25 women are randomly selected, find the probability that they have a mean height greater than 68 inches. Draw a bell curve, label your mean, and shade the area that you are trying to find. Then answer the question. *(Round to 4 decimal places)*

**Steps to Solve:**

1. **Identify the Parameters**:
   - Mean (\(\mu\)) = 67.5 inches
   - Standard Deviation (\(\sigma\)) = 2.5 inches
   - Sample size (n) = 25
   - Sample mean to compare = 68 inches

2. **Calculate the Standard Error**:
   - Standard Error (SE) = \(\frac{\sigma}{\sqrt{n}} = \frac{2.5}{\sqrt{25}} = \frac{2.5}{5} = 0.5\)

3. **Calculate the Z-score**:
   - Z = \(\frac{X - \mu}{SE} = \frac{68 - 67.5}{0.5} = 1\)

4. **Find the Probability**:
   - Use the standard normal distribution table or a calculator to find the probability corresponding to a Z-score of 1.
   - Probability (P) = 1 - P(Z ≤ 1)

5. **Draw the Bell Curve**:
   - A bell curve representing the normal distribution is drawn.
   - The mean (\(\mu = 67.5\)) is marked in the center of the curve.
   - The region to the right of 68 inches is shaded to represent the area for which you are finding the probability.

**Outcome:**
- Calculate the probability of selecting 25 women with a mean height greater than 68 inches based on the Z-score and standard normal distribution table.
- Ensure to round the probability to 4 decimal places as instructed.

**Questions for Understanding:**

- What is a normal distribution, and why is it important in statistics?
- How can the concept of standard error assist in understanding sample means?
- What is a Z-score, and how does it help in finding probabilities?

This exercise provides a practical application of the statistical concepts of normal distribution
Transcribed Image Text:**Educational Content: Understanding Probability with Normal Distribution** --- **Problem Statement:** Assume the heights of women are normally distributed with a mean of 67.5 inches and a standard deviation of 2.5 inches. If 25 women are randomly selected, find the probability that they have a mean height greater than 68 inches. Draw a bell curve, label your mean, and shade the area that you are trying to find. Then answer the question. *(Round to 4 decimal places)* **Steps to Solve:** 1. **Identify the Parameters**: - Mean (\(\mu\)) = 67.5 inches - Standard Deviation (\(\sigma\)) = 2.5 inches - Sample size (n) = 25 - Sample mean to compare = 68 inches 2. **Calculate the Standard Error**: - Standard Error (SE) = \(\frac{\sigma}{\sqrt{n}} = \frac{2.5}{\sqrt{25}} = \frac{2.5}{5} = 0.5\) 3. **Calculate the Z-score**: - Z = \(\frac{X - \mu}{SE} = \frac{68 - 67.5}{0.5} = 1\) 4. **Find the Probability**: - Use the standard normal distribution table or a calculator to find the probability corresponding to a Z-score of 1. - Probability (P) = 1 - P(Z ≤ 1) 5. **Draw the Bell Curve**: - A bell curve representing the normal distribution is drawn. - The mean (\(\mu = 67.5\)) is marked in the center of the curve. - The region to the right of 68 inches is shaded to represent the area for which you are finding the probability. **Outcome:** - Calculate the probability of selecting 25 women with a mean height greater than 68 inches based on the Z-score and standard normal distribution table. - Ensure to round the probability to 4 decimal places as instructed. **Questions for Understanding:** - What is a normal distribution, and why is it important in statistics? - How can the concept of standard error assist in understanding sample means? - What is a Z-score, and how does it help in finding probabilities? This exercise provides a practical application of the statistical concepts of normal distribution
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