Suppose we have this program: int main() { printf("d"); fork(); printf("f"); } We expect it to print "dff", but when we run it, it prints "dfdf". Why?
Suppose we have this program: int main() { printf("d"); fork(); printf("f"); } We expect it to print "dff", but when we run it, it prints "dfdf". Why?
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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Question
Suppose we have this program:
int main() {
printf("d");
fork();
printf("f");
}
We expect it to print "dff", but when we run it, it prints "dfdf". Why?
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Expert Solution
Step 1
Here fork() statement will create a new child process.
The process will be a replica of parent process and thus it will contain all the print statement like the parent process.
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