Suppose we construct a galvanic cell by placing two identical platinum electrodes in two beakers that are connected by a salt bridge. One beaker contains 1.0 M HCI, and the other a 0.010 M solution of Na;SO. at pH 7.00. Both cells are in contact with the atmosphere, with PO2PO2 = 0.20 atm. If the relevant electrochemical reaction in both compartments is the four-electron reduction of oxygen to water: Ozg) + 4H* (aq) + 4e - 2H20() What will be the potential when the circuit is closed?

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Suppose we construct a galvanic cell by placing two identical platinum electrodes in two beakers
that are connected by a salt bridge. One beaker contains 1.0 M HCI, and the other a 0.010 M
solution of NaSO4 at pH 7.00. Both cells are in contact with the atmosphere, with PO2PO2 = 0.20
atm. If the relevant electrochemical reaction in both compartments is the four-electron reduction
of oxygen to water:
Oz(9) + 4H* (aq)+ 4e¯ →
• 2H20M
What will be the potential when the circuit is closed?
Transcribed Image Text:Suppose we construct a galvanic cell by placing two identical platinum electrodes in two beakers that are connected by a salt bridge. One beaker contains 1.0 M HCI, and the other a 0.010 M solution of NaSO4 at pH 7.00. Both cells are in contact with the atmosphere, with PO2PO2 = 0.20 atm. If the relevant electrochemical reaction in both compartments is the four-electron reduction of oxygen to water: Oz(9) + 4H* (aq)+ 4e¯ → • 2H20M What will be the potential when the circuit is closed?
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