A certain metal M forms a soluble sulfate salt MSO4. Suppose the left half cell of a galvanic cell apparatus is filled with a 5.00 M solution of MSO4 and the right half cell with a 2.50 mM solution of the same substance. Electrodes made of M are dipped into both solutions and a voltmeter is connected between them. The temperature of the apparatus is held constant at 30.0 °C. Which electrode will be positive? What voltage will the voltmeter show? Assume its positive lead is connected to the positive electrode. Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits. O left O right 0 x10 X
A certain metal M forms a soluble sulfate salt MSO4. Suppose the left half cell of a galvanic cell apparatus is filled with a 5.00 M solution of MSO4 and the right half cell with a 2.50 mM solution of the same substance. Electrodes made of M are dipped into both solutions and a voltmeter is connected between them. The temperature of the apparatus is held constant at 30.0 °C. Which electrode will be positive? What voltage will the voltmeter show? Assume its positive lead is connected to the positive electrode. Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits. O left O right 0 x10 X
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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### Questions
1. **Which electrode will be positive?**
- [ ] left
- [ ] right
2. **What voltage will the voltmeter show? Assume its positive lead is connected to the positive electrode.**
Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.
\[\boxed{\phantom{0}} \]
### Explanation of the graph/diagram:
The diagram demonstrates a galvanic cell setup where each half-cell contains a metal electrode M submerged in respective MSO₄ solutions of different molar concentrations. The left cell contains a higher concentration solution (5.00 M), and the right cell has a lower concentration solution (2.50 mM). A voltmeter is connected to the electrodes to measure the potential difference between the two half-cells.
**Temperature:** The temperature is constant at 30.0 °C.
Understanding which electrode will be positive and measuring the voltage across the two half-cells can help in understanding the electrochemical behavior of metal M and its respective sulfate salt, MSO₄.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fffa72a4c-ccb8-45dd-a189-a93d0336c585%2F55592e6d-dab1-4313-bf7f-6187cdd5a4c8%2Fa4wyu4_processed.png&w=3840&q=75)
Transcribed Image Text:### Galvanic Cell Experiment: Soluble Sulfate Salt MSO₄
A certain metal **M** forms a soluble sulfate salt \( \text{MSO}_4 \). Suppose the left half-cell of a galvanic cell apparatus is filled with a \( 5.00 \, \text{M} \) solution of \( \text{MSO}_4 \) and the right half-cell is filled with a \( 2.50 \, \text{mM} \) solution of the same substance. Electrodes made of **M** are dipped into both solutions, and a voltmeter is connected between them. The temperature of the apparatus is held constant at \( 30.0 \, °\text{C} \).
### Questions
1. **Which electrode will be positive?**
- [ ] left
- [ ] right
2. **What voltage will the voltmeter show? Assume its positive lead is connected to the positive electrode.**
Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.
\[\boxed{\phantom{0}} \]
### Explanation of the graph/diagram:
The diagram demonstrates a galvanic cell setup where each half-cell contains a metal electrode M submerged in respective MSO₄ solutions of different molar concentrations. The left cell contains a higher concentration solution (5.00 M), and the right cell has a lower concentration solution (2.50 mM). A voltmeter is connected to the electrodes to measure the potential difference between the two half-cells.
**Temperature:** The temperature is constant at 30.0 °C.
Understanding which electrode will be positive and measuring the voltage across the two half-cells can help in understanding the electrochemical behavior of metal M and its respective sulfate salt, MSO₄.
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