Suppose the wire has a 10Ω resistance (which is almost certainly an overestimate) and the voltmeter has a 1MΩ resistance (1Ω=1s/F). Given that our capacitances are of order ~10μF, compute the time constant for each resistance: this is essentially the time it takes for current to "go through" that component. From these timescales, consider: of the two processes described above (the quick change in voltage and the slow change in voltage), which process is controlled by each component's resistance? On very long timescales (minutes-to-hours), the voltmeter can essentially be considered as another wire - current can pass through it given enough time. Based on this, if we were to leave the capacitors in Part I in the left (capacitors charged) position for a very long time, what voltages would you observe on each capacitor? What if we left the capacitors in Part II in the right (capacitors connected together) position for a very long time?
Suppose the wire has a 10Ω resistance (which is almost certainly an overestimate) and the voltmeter has a 1MΩ resistance (1Ω=1s/F). Given that our capacitances are of order ~10μF, compute the time constant for each resistance: this is essentially the time it takes for current to "go through" that component. From these timescales, consider: of the two processes described above (the quick change in voltage and the slow change in voltage), which process is controlled by each component's resistance?
On very long timescales (minutes-to-hours), the voltmeter can essentially be considered as another wire - current can pass through it given enough time. Based on this, if we were to leave the capacitors in Part I in the left (capacitors charged) position for a very long time, what voltages would you observe on each capacitor? What if we left the capacitors in Part II in the right (capacitors connected together) position for a very long time?
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