R, = 8 kN R, = 8 kN V, = 2.8 V V, = 2.5 V V, = 2.8 V V, = 2.5 V R, = 4 kN R, = 4 kN R, = 4 kN R, = 4 kN I2 A
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(a)
Current through each resistor in part(A) in mA.
(b)
Current through each resistor in part(B) in mA.
(c)
Power consumed by each circuit in mW.
Given,
Circuit diagrams,
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- v can be determined from: morbol Combining like terms gives: e where AV- accelerating voltage. Rearranging gives: 2eAV m Substitution of (equation 2) into (equation 1) gives: Data N R V T 1 2 m I 22 v² = mv² = eAV, 150 2V nottom of B²r² e 1 2eV m Br mm, qque aswog ogslov rigid lino sifodinilladut m Procedure: C xt)s (equation 2) Sad m 99781 0.140[m] 150 V 2.15CM 10.0215 M 2.04 (equation 3) 1. Set the accelerating voltage and current as given by the instructor.non W 2. Measure the diameter of the circle formed by the electron beam with the centimeter scale next to the vacuum tube. Record the radius of the beam in the data table (not the diameter). :noftaups 901 maoil bur N R V T 101 I Insanal del inobra woman de 190hef de (012) 150 turns 0.140[m] I, SA M 200 V 123.3 cm 0.033mHow many joules are in 1 kWh (kilowatthour)?