Analysis of Data The magnetic field produced by the Helmholtz coil at the center of the coil (at the position of the vacuum tube) is given by: 8μ.N1 R√125 Where N is the number of turns in one of the circular coils of the Helmholtz coil and Ris the radius of the coil. B = 1. Calculate B using the equation above. 2. Calculate e/m using equation 3. e 2V B²2 3. Calculate e/m using data from your textbook (accepted truth value). end 4. Calculate the % error between your experimental data and the accepted truth value.
Analysis of Data The magnetic field produced by the Helmholtz coil at the center of the coil (at the position of the vacuum tube) is given by: 8μ.N1 R√125 Where N is the number of turns in one of the circular coils of the Helmholtz coil and Ris the radius of the coil. B = 1. Calculate B using the equation above. 2. Calculate e/m using equation 3. e 2V B²2 3. Calculate e/m using data from your textbook (accepted truth value). end 4. Calculate the % error between your experimental data and the accepted truth value.
Chapter7: Electricity
Section: Chapter Questions
Problem 3Q
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Question
Transcribed Image Text:Analysis of Data
The magnetic field produced by the Helmholtz coil at the center of the coil (at the
position of the vacuum tube) is given by:
8μ.NI
R√125
Where N is the number of turns in one of the circular coils of the Helmholtz coil and R is
the radius of the coil.
B =
1. Calculate B using the equation above.
Charge 20 mus
2. Calculate e/m using equation 3.
عمال
11
/m)
2V
B²,²
3. Calculate e/m using data from your textbook (accepted truth value).
= e( x B)
4. Calculate the % error between your experimental data and the accepted truth value.
![v can be determined from:
morbol
Combining like terms gives:
e
where AV- accelerating voltage. Rearranging gives:
2eAV
m
Substitution of (equation 2) into (equation 1) gives:
Data
N
R
V
T
1
2
m
I
22
v² =
mv² = eAV,
150
2V
nottom of
B²r²
e 1 2eV
m
Br
mm, qque aswog ogslov rigid lino sifodinilladut m
Procedure:
C
xt)s
(equation 2)
Sad
m
99781
0.140[m]
150 V
2.15CM 10.0215
M
2.04
(equation 3)
1. Set the accelerating voltage and current as given by the instructor.no W
2. Measure the diameter of the circle formed by the electron beam with the centimeter
scale next to the vacuum tube. Record the radius of the beam in the data table (not the
diameter).
noftsups 901 maoil bur
N
R
V
T
101
I
Insanal del
inobra
woman de
190hef de
(012)
150 turns
0.140[m]
I, SA
M
200 V
123.3 CM 0. 033m](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F50351a65-5e52-4545-9e5a-caf58e03b0d0%2F8ee1dffd-672a-4936-a412-0529c6fa8801%2Fvtxbmpk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:v can be determined from:
morbol
Combining like terms gives:
e
where AV- accelerating voltage. Rearranging gives:
2eAV
m
Substitution of (equation 2) into (equation 1) gives:
Data
N
R
V
T
1
2
m
I
22
v² =
mv² = eAV,
150
2V
nottom of
B²r²
e 1 2eV
m
Br
mm, qque aswog ogslov rigid lino sifodinilladut m
Procedure:
C
xt)s
(equation 2)
Sad
m
99781
0.140[m]
150 V
2.15CM 10.0215
M
2.04
(equation 3)
1. Set the accelerating voltage and current as given by the instructor.no W
2. Measure the diameter of the circle formed by the electron beam with the centimeter
scale next to the vacuum tube. Record the radius of the beam in the data table (not the
diameter).
noftsups 901 maoil bur
N
R
V
T
101
I
Insanal del
inobra
woman de
190hef de
(012)
150 turns
0.140[m]
I, SA
M
200 V
123.3 CM 0. 033m
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