Suppose the state of RAM is as follows: RAM 6 1 0 2 1 3 2 + 5 5 4 6 3 Consider the following assembly code: 1234567 1 $1 A = M A = M A = M D = M @4 7 M=D What will be the value of RAM[4] following the code execution?
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- The following byte sequence is the machine code of a program function compiled with the Y86- 64 instruction set. The memory address of the first byte is 0x300. Note that the byte sequence is written in hex-decimal form, i.e., each number/letter is one hex-decimal number representing 4 binary bits, and two numbers/letters represent one byte. 630030F3020000000000000030F11E000000000000007023030000000 00000601061316211761F0300000000000090- Please write out the assembly instructions (in Y86-64 instruction set) corresponding to the machine codes given by the above bytes sequence, and explain what this program function is computing. The machine has a little-endian byte ordering.Microprocessor8086 Write the assembly of Write on the data segment and create number1 and number2 variables in byte size and initialize the variables Then compute the sum ,subtraction,multiplication and division of the defined variables and load the values to the variables which you create on the data segment Perform the operations below in sequence with defined on the data segment numbers in array Find the sum of array and average of array Find the maximum and minimum numbers of array If it’s possible on emu8086 appComputer science
- Computer organization and assembly language Please help me with this. I have to write line by line what each line of codes does. CODE IS BELOW: .model small .386 .stack 100h .data msg1 db 13, 10, "Enter any number --> ", "$" msg2 db "Enter an operation +,- * or / --> ",13, 10, "$" msg3 db "The Operation is --> ", "$" msg4 db "The result is --> ", "$" By_base dd 21 by_10 dd 10 ; 32 bits variable with initial value = 10 sp_counter db 0 ; 8 bits variable with initial value of zero disp_number dd 0 ; 32 bits variable with initial value = 0 disp_number2 dd 0 disp_number3 dd 0 op_type db 0 last_key dd 0 ; 32 bits variable with initial value of zero remainder db 0 .code main proc mov ax,@data;set up datasegment movds,ax mov dx,offset msg1 call display_message callm_keyin calloperation mov dx,offset msg1 calldisplay_message callm_keyin cmpop_type, "+" jnz short skip_plus callop_plus skiP_plus: cmp op_type, "-" jnz short skip_minus callop_minus…solve fast | microprocessor 8086Please your code should be in mips assembly language
- COMPUTER ORGANISATION : Use RARS simulator to write and execute the two codes below using RISC-V Assembly language.80x86 Intel Assembly language Write an 80x86 Intel assembly language program: Declare two integer arrays and initialize the first one with 7, 6, 5, 4 and 3. Initialize the second one with 3, 6, 9, 10, 15 Declare the third array of the same size but do not initialize. Your program must initialize ESI and EDI to have the addresses of the array1 and array2 respectively. Use EBX and place the address of the third array in that register. Use these registers to add the first element of the first array to the first element of the second array and place the result in the third array. Updated the values of these registers so all of them refer to the next location.subject microprocessor and assembly language Create a procedure that fills an array of doublewords with N random integers, making sure the values fall within the range j...k, inclusive. When calling the procedure, pass a pointer to the array that will hold the data, pass N, and pass the values of j and k. Preserve all register values between calls to the procedure. Write a test program that calls the procedure twice, using different values for j and k. Verify your results using a debugger.
- Systems Programming Purpose: The purpose of this assignment is to practice loop instructions and array iterations in M6800 assembly language programming. Write an assembly language program which implements the following C code that is a find minimum problem solution implementation: int A[10] = {8, 14, 6, 16, 5, 5, 10, 9, 4, 11}; int i = 0; int min = 255; // This is the largest number 8-bit accumulators can hold. while (i < 10) { if (A[i] < min) min = A[i]; } Your solution should be able to handle all possible array elements and orderings for any value an accumulator can hold. You should treat variable į as XR in assembler (index register) and store variable min in the address 60H. 0010: 00 00 00 00 00 00 00 00 0O 00 00 00 00 00 00 00 8628: 00 060 00 00 00 600 00 00 00 08 08 00 6 00 00 00 0030: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 0040: 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 0050: 00 G0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 006 0: 00 00 00 00 00 00 00 00 00 08 00…ADD [R1], R2, [R3]; Here [R1] and [R3] indicate memory locations pointed by R1 and R3 register respectively. Here the operand field next to opcode will hold the result at the end. Assume that the machine code of this instruction is loaded at address 1020H of the main memory. Also assume that the contents of registers R1, R2 and R3 are 2001H, 2002H and 2003H respectively. Moreover, 1000H, 2000H and 3000H are saved at memory addresses 2001H, 2002H and 2003H respectively. a) Draw a schematic diagram of a CPU, show its important functional units required to process this instruction.ASSEMBLY LANGUAGE CODE 80x86 only Using the windows32 or windows64 framework, write a program that inputs a collection of integers into an array of doublewords and then sequentially searches for values stored in the array. Implement the following design.