int oddCount = 0; int evenCount = 0; // To initialize the array, declare array to have M-1 (e.g. point to R1) // Then directly initialize each of the elements {1, 1, 3, 5, 8, 13, 21, 34, 55, 89 } // in registers R1, ..., R10 respectively int[] array = { 1, 1, 3, 5, 8, 13, 21, 34, 55, 89 }; // Loop through all 10 indices of the array for (int i = 0; i < 10; i++) { // If the array element bitwise and with 1 is equal to 0, increment even count if ((array[i] & 1) == 0) evenCount++; // Otherwise, increment odd count else oddCount++; }
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I need help please to Translate the pictured Java code into Hack Assembly programming language using/including the following code as part
@i
D=M
@array
A=M
A=D+A
D=M
@1
D=D&A
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- arl = np.array([10,20,30,40]) ar2 = np.array([15,6,7]) np.vstack ( (arl,ar2)) The np.stack() function above will O a. Give error b. Stack the two arrays ar1 and ar2 horizontally c. Stack the two arrays ar1 and ar2 vertically O d. Sums the two arrays art and ar2in c++ language#include using namespace std; main() { int num array[] = (1, 2, 3, 4, 5, 6, 7, 8, 9, 10}; for (int n-1; n<-5;++n) { cout <« n<< * "; } return 0; Out put : 1 23 4 567 89 10 O Out put : 3 4 56789 10 O Out put : 2 3 45 67 89 10 11 O Out put : 1 2 3 456 Out put : 1 2 345 Not listed O
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