int oddCount = 0; int evenCount = 0; // To initialize the array, declare array to have M-1 (e.g. point to R1) // Then directly initialize each of the elements {1, 1, 3, 5, 8, 13, 21, 34, 55, 89 } // in registers R1, ..., R10 respectively int[] array = { 1, 1, 3, 5, 8, 13, 21, 34, 55, 89 }; // Loop through all 10 indices of the array for (int i = 0; i < 10; i++) { // If the array element bitwise and with 1 is equal to 0, increment even count if ((array[i] & 1) == 0) evenCount++; // Otherwise, increment odd count else oddCount++; }

EBK JAVA PROGRAMMING
9th Edition
ISBN:9781337671385
Author:FARRELL
Publisher:FARRELL
Chapter8: Arrays
Section: Chapter Questions
Problem 15RQ
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I need help please to Translate the pictured Java code into Hack Assembly programming  language  using/including the following code as part

@i

D=M

@array

A=M

A=D+A

D=M

@1

D=D&A

int oddCount =
0;
int evenCount = 0;
// To initialize the array, declare array to have M-1 (e.g. point to R1)
// Then directly initialize each of the elements {1, 1, 3, 5, 8, 13, 21, 34, 55, 89 }
// in registers R1, ..., R10 respectively
int[] array = { 1, 1, 3, 5, 8, 13, 21, 34, 55, 89 };
// Loop through all 10 indices of the array
for (int i = 0; i < 10; i++)
{
// If the array element bitwise and with 1 is equal to 0, increment even count
if ((array[i] & 1) == 0)
evenCount++;
// Otherwise, increment odd count
else
oddCount++;
}
Transcribed Image Text:int oddCount = 0; int evenCount = 0; // To initialize the array, declare array to have M-1 (e.g. point to R1) // Then directly initialize each of the elements {1, 1, 3, 5, 8, 13, 21, 34, 55, 89 } // in registers R1, ..., R10 respectively int[] array = { 1, 1, 3, 5, 8, 13, 21, 34, 55, 89 }; // Loop through all 10 indices of the array for (int i = 0; i < 10; i++) { // If the array element bitwise and with 1 is equal to 0, increment even count if ((array[i] & 1) == 0) evenCount++; // Otherwise, increment odd count else oddCount++; }
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