Suppose the P-value in a two-tailed test is 0.0134. Based on the same population, sample and null hypothesis,and assuming the test statistic z is negative, what is the P-value for a corresponding left-tailed test?Select one:O a. 0.0067O b. 0.0268O c. 0.225O d. 0.0184Next pag

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Answered: Suppose the P-value in a two-tailed…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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If you use a 0.03 level of significance in a (two-tail) hypothesis test, what is your decision rule for rejecting a null hypothesis that the population mean is 650 if you use the Z test? Which of the following decision rules is correct? A. Reject H0 if −1.88<ZSTAT<+1.88. B. Reject H0 if ZSTAT<−1.88 or ZSTAT>+1.88. C. Reject H0 if ZSTAT<−2.17 or ZSTAT>+2.17. D. Reject H0 if −2.17<ZSTAT<+2.17.
In an experiment to study the dependence of hypertension on smoking habits, the data below were taken on 167 individuals. Test the hypothesis that the presence or absence of hypertension is independent of smoking habits. perform a Chi-Square test for Independence on this data. Use a 0.01 level of significance. a. What are the null and alternate hypotheses? b. What is the value of the Chi-Square statistic and its corresponding Pearson Chi-Square probability? c. What is your conclusion? Accept or Reject the Null Hypothesis with a justification based on the p-value.
a particular hypothesis test is left-tailed, and the area to the left of the test statistic is 0.20. what is the p-value?
A significance test is conducted for which the alternative hypothesis states that more than 83 percent of all adult sea turtles on a certain beach are female. A random sample of adult sea turtles from the beach found that 85 percent of the sea turtles were female. The pp-value for the test is 0.4058. If the null hypothesis is true, which of the following statements is a correct interpretation of the pp-value? Of all possible samples of the same size, 40.58 percent will result in 85 percent of adult sea turtles on the beach being female. Of all possible samples of the same size, 40.58 percent will result in 85 percent of adult sea turtles on the beach being female., A Of all possible samples of the same size, 40.58 percent will result in 85 percent or more of adult sea turtles on the beach being female. Of all possible samples of the same size, 40.58 percent will result in 85 percent or more of adult sea turtles on the beach being female., B Of all possible…
Given the information: s? =4. s? =6 n, =15 n, =25 the number of degrees of freedom that should be used in the pooled variance t-test is:
5. A one-way ANOVA test is conducted and finds the following results: n = 34, K = 4, x̅ = 8.32, MST = 26.723, and MSE = 14.767. What is the test statistic, F, for this ANOVA test? B. 1.81 D. 3.69 C. 3.21 A. 1.77 6. A hypothesis test is conducted with H0 : p1 - p2 = 0 vs. Ha: p1 - p2 ≠ 0 . What is the tail area of the hypothesis test given the sample data: n1= 121, p1=0.79, n2= 81, p2 = 0.67 C. 0.0614 B. 0.0536 A. 0.0268 D. 0.0307
The mean voltage and standard deviation of 10 batteries from each manufacturer were measured. The results are summarized in the following table. Manufacturer Sample mean voltage (millivolts) Sample standard deviation (millivolts) A 136 3 B 132 5 What type of hypothesis test should be performed? What is the test statistic? What is the number of degrees of freedom? Does sufficient evidence exist to support the claim that the voltage of the batteries made by the two manufacturers is different at the α=0.1 significance level?
The value obtained for the test statistic, z, in a one-mean z-test is given. Whether the test is two tailed, left tailed, or right tailed is also specified. For parts (a) and (b), determine the P-value and decide whether, at the 1% significance level, the data provide sufficient evidence to reject the null hypothesis in favor of the alternative hypothesis. a. The test statistic in a two-tailed test is z = -0.93. The P-value is (Round to three decimal places as needed.) ... sufficient evidence to reject the null hypothesis in favor of the significance level. At the 1% significance level, the data the alternative hypothesis because the obtained P-value is b. The test statistic in a two-tailed test is z = 0.61. The P-value is (Round to three decimal places as needed.) sufficient evidence to reject the null hypothesis in favor of the significance level. At the 1% significance level, the data the alternative hypothesis because the obtained P-value is Time Remaining: 01:57:58 Mand

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Suppose the P-value in a two-tailed test is 0.0134. Based on the same population, sample and null hypothesis, and assuming the test statistic z is negative, what is the P-value for a corresponding left-tailed test? Select one: O a. 0.0067