The mean voltage and standard deviation of 14 batteries from each manufacturer were measured. The results are summarized in the following table. Manufacturer Sample mean voltage (millivolts) Population standard deviation(millivolts) A 119 4 B 116 1 What type of hypothesis test should be performed? What is the test statistic? What is the number of degrees of freedom? Does sufficient evidence exist to support the claim that the voltage of the batteries made by the two manufacturers is different at the α=0.1 significance level?yes or no
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| Manufacturer | Sample mean voltage (millivolts) | Population standard deviation(millivolts) |
|---|---|---|
| A | 119 | 4 |
| B | 116 | 1 |
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- You are interested in investigating whether the type of computer a person primarily uses and the type of car they drive are dependent. The table below shows the results of a survey. α = 0.01 significance level. Sedan SUV Truck Tablet 100 95 60 Notebook 119 106 37 Desktop 112 103 27 The test-statistic for this data =_____ (Please show your answer to three decimal places.) The p-value for this sample =_____ (Please show your answer to four decimal places.)The cooling system in a nuclear submarine consists of an assembly of welded pipes through which a coolant is circulated. Specifications require that weld strength must exceed 150 psi. A random sample of 20 welds resulted in a sample mean of 153.7 psi and a sample standard deviation of 11.3 psi. What is the appropriate alternative hypothesis for the problem? O mean 150 O mean = 150 mean # 153.5A company manufactures electrical components and today they are producing 220-ohm carbon film resistors. A sample of 8 resistors was taken from the production line and were tested. Below are the measured resistance of the 8 resistors. [220.8, 221.9, 223.2, 219.1, 222.8, 219.2, 219.4, 219.5] Consider the two-sided hypothesis test for the mean resistance: Ho : µ = 220 vs Hj : µ # 220 Calculate the test statistic for the observed data for this hypothesis test. Give your answer to 3 decimal places. Test statistic: to 3 d.p. What is your hypothesis decision given that the manufacturing company is happy with a 5% significance level of the test? Hypothesis Decision: (No answer given) You may use the following quantile values from the Student-t distribution: df 7 8 pt(0.900, df) 1.415 1.397 1.383 pt(0.950, df) 1.895 1.860 1.833 pt(0.975, df) 2.365 2.306 2.262
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- A study was done using a treatment group and a placebo group. The results are shown in the table. Assume that the two samples are independent simple random H samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. a. Test the claim that the two samples are from populations with the same mean. What are the null and alternative hypotheses? OA. Ho: #₁ = 1₂ H₁: H₁ H₂ OC. Ho: H₁The mean voltage and standard deviation of 10 batteries from each manufacturer were measured. The results are summarized in the following table. Manufacturer Sample mean voltage (millivolts) Sample standard deviation (millivolts) A 136 3 B 132 5 What type of hypothesis test should be performed? What is the test statistic? What is the number of degrees of freedom? Does sufficient evidence exist to support the claim that the voltage of the batteries made by the two manufacturers is different at the α=0.1 significance level?Calculate the test statistic (t) and p-value.During an economic crisis, the average value of homes in a community of 36 homes lost $9445 with a standard deviation of $1300. The average home value in the region lost $8990. Was this community of 36 homesunusual? Use a t-test to decide if the average loss observed was significantly different from the region value. Use a level of significance α=0.05. Identify the hypotheses for the test. H0: μ ▼ not equals≠ equals= greater than> less than< nothing HA: μ ▼ equals= greater than> not equals≠ less than< nothing The test statistic is nothing. (Round to two decimal places as needed.) The P-value is nothing. (Round to three decimal places as needed.) What is the conclusion of the test? Was the average loss observed significantly different from the region value? ▼ Reject Fail to reject the null hypothesis because the P-value is ▼ greater less than the given significance level, and conclude that the…Records indicate that the mean weight of mature rainbow trout in Eagle Creek is 2.25 kg with a standard deviation of 0.53 kg. After years of marked oxygen depletion from pollutants in the creek, you want to perform a hypothesis test to see if the standard deviation, σ, of weights has changed. To do so, you measure the weights of 16 randomly chosen mature rainbow trout from the creek and find that the sample standard deviation is 0.34 kg. Under the assumption that current weights of mature rainbow trout in the creek follow a normal distribution, you will perform a chi-square test.Find χ2, the value of the test statistic for your chi-square test. Round your answer to three or more decimal places.=χ2Data on the weights (Ib) of the contents of cans of diet soda versus the contents of cans of the regular version of the soda is summarized to the right. Assume that the two samples are independent simple random samples selected from normally distributed populations, and do not assume that the population standard deviations are equal. Complete parts (a) and (b) below. Use a 0.01 significance level for both parts. Diet Regular H2 26 26 0.79911 Ib 0.81326 Ib S 0.00445 Ib 0.00759 Ib ..... a. Test the claim that the contents of cans of diet soda have weights with a mean that is less than the mean for the regular soda. What are the null and alternative hypotheses? A. Ho: Hy =H2 H1: 41> H2 B. Ho: H1 = H2 H1: 41SEE MORE QUESTIONSRecommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons Inc
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