Suppose the average height of Filipinos is 5 feet and 2 inches (157.48 cm). Determine if there is enough evidence to prove that the average height is different from 157.48 cm and reject this claim by creating a hypothesis test using the GIVEN YOU SEE BELOW as the sample. Assume your data is approximately normal. Use a 5% level of significance. Please don't use excell as computation. And write the solution in MICROSOFT WORD or in your papers. Thank you!
Suppose the average height of Filipinos is 5 feet and 2 inches (157.48 cm). Determine if there is enough evidence to prove that the average height is different from 157.48 cm and reject this claim by creating a hypothesis test using the GIVEN YOU SEE BELOW as the sample. Assume your data is approximately normal. Use a 5% level of significance. Please don't use excell as computation. And write the solution in MICROSOFT WORD or in your papers. Thank you!
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
TOPIC: Hypothesis Testing of Sample Mean
QUESTION:
Suppose the average height of Filipinos is 5 feet and 2 inches (157.48 cm). Determine if there is enough evidence to prove that the average height is different from 157.48 cm and reject this claim by creating a hypothesis test using the GIVEN YOU SEE BELOW as the sample. Assume your data is approximately normal. Use a 5% level of significance. Please don't use excell as computation. And write the solution in MICROSOFT WORD or in your papers. Thank you!
GIVEN:
169
165.099
160.02
152.40
EXAMPLE:
(IMAGE YOU SEE IN ATTACHMENT)
Transcribed Image Text:Example:
1. The mean length of the lumber is supposed to be 8.5 feet. A builder wants to check whether the shipment of lumber
she receives has a mean length different from 8.5 feet. If the builder observes that the sample mean of 61 pieces of
lumber is 8.3 feet with a sample standard deviation of 1.2 feet, what will she conclude? Conduct this test at a 1% level of
significance.
Conduct the test using the Rejection Region approach.
n = 61
: nommal
7 = 8.3F+
Ft
S = 1.2 ft
α = 1% = 0.01
Mo = 8.5 ft
t*.
=
Ho: u
На м
1: FAIL TO REJECT H₂
μ = 8.5Ft
L = 0.01
2/2 = 0.005
5-M
in
# 8.0 Ft (2TT)
S
06/2 - 0.005
JF=61-1·60 toc = ± 2.660
ta
-2.660
8.3 8.5
12/ब
1302
1%
/ 10
+2.660
-1.302
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