Suppose that random variable X has a normal distribution with mean μ standard deviation σ = 4, so that X - N(10,4). Find: a) a x0.05 such that Pr(X ≤ 0.05) = 0.05, x0.05 = b) a x 0.975 such that Pr(|X|X0.975) = 0.95, X0.975 = = 10 and c) the 75th percentile of the distribution of X. That is, the value X0.75 such that Pr(Xx0.75) 0.75. X0.75 +0.75= =
Suppose that random variable X has a normal distribution with mean μ standard deviation σ = 4, so that X - N(10,4). Find: a) a x0.05 such that Pr(X ≤ 0.05) = 0.05, x0.05 = b) a x 0.975 such that Pr(|X|X0.975) = 0.95, X0.975 = = 10 and c) the 75th percentile of the distribution of X. That is, the value X0.75 such that Pr(Xx0.75) 0.75. X0.75 +0.75= =
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.8: Probability
Problem 31E
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Question
Suppose that random variable X has a

Transcribed Image Text:Suppose that random variable X has a normal distribution with mean μ
standard deviation σ = 4, so that X - N(10,4). Find:
a) a x0.05 such that Pr(X ≤ 0.05) = 0.05,
x0.05 =
b) a x 0.975 such that Pr(|X|X0.975) = 0.95,
X0.975
=
= 10 and
c) the 75th percentile of the distribution of X. That is, the value X0.75 such that
Pr(Xx0.75) 0.75.
X0.75 +0.75=
=
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