Suppose that variable z has a standard normal distribution. Use the attached table to findthe particular z value (zo) that satisfies(a) Pr (z ≥ zo) = .0099,(b) Pr (z ≤zo) = .8907, (c) Pr(z ≤ zo) = .0179,(d) Pr(z ≥ zo) = .6985,(e) Pr(-zo ≤ z ≤ zo) = .5762, (f) Pr(zo ≤ z ≤1.00) = .7056. Appendix I Table of the Standard Normal DistributionThe entries in this table are the probabilities that a standard normalvariate will have a value between 0 and z.265599THERE123400400080083208711217 1255.03 .0420090910 09481293 13311628 1664 17001985 20190506 07 .08 090192 0626 0675 0714 07530987 1026 1064 1103 11411368 14061443 1480 15171736 1772 1808 184420882157 2190 2224996 49960.49997, 0.4999997, and 0.499999999, respectively.

Answered: the particular z value (zo) that…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Question

Suppose that variable z has a standard normal distribution. Use the attached table to find
the particular z value (z_o) that satisfies
(a) Pr (z ≥ z_o) = .0099,
(b) Pr (z ≤z_o) = .8907,
(c) Pr(z ≤ z_o) = .0179,
(d) Pr(z ≥ z_o) = .6985,
(e) Pr(-z_o ≤ z ≤ z_o) = .5762,
(f) Pr(z_o ≤ z ≤1.00) = .7056.

Appendix I Table of the Standard Normal Distribution
The entries in this table are the probabilities that a standard normal
variate will have a value between 0 and z.
2
65599
THERE
1234
00400080
0832
0871
1217 1255
.03 .04
2009
0910 0948
1293 1331
1628 1664 1700
1985 2019
05
06 07 .08 09
0192 0626 0675 0714 0753
0987 1026 1064 1103 1141
1368 1406
1443 1480 1517
1736 1772 1808 1844
2088
2157 2190 222
4996 4996
0.49997, 0.4999997, and 0.499999999, respectively.

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Expert Solution

Step 1

given data

standard normal distribution

Z~N(0,1)

we have to find value of z₀ so that,

(a) Pr (z ≥ z_o) = .0099,
(b) Pr (z ≤z_o) = .8907,
(c) Pr(z ≤ z_o) = .0179,
(d) Pr(z ≥ z_o) = .6985,
(e) Pr(-z_o ≤ z ≤ z_o) = .5762,
(f) Pr(z_o ≤ z ≤1.00) = .7056.