Suppose that the lifetime of a component (in hours), X, is modeled with a Weibull distribution with ß = 0.5 and 6 = 3400. Determine the following in parts (a) and (b). P(X >3500) = a. b. P(X > 6000|X >3000) = c. Suppose that Xhas an exponential distribution with mean equal to 3400. Determine P(X 6000 X 3000) =
Suppose that the lifetime of a component (in hours), X, is modeled with a Weibull distribution with ß = 0.5 and 6 = 3400. Determine the following in parts (a) and (b). P(X >3500) = a. b. P(X > 6000|X >3000) = c. Suppose that Xhas an exponential distribution with mean equal to 3400. Determine P(X 6000 X 3000) =
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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![Suppose that the lifetime of a component (in hours), X, is modeled with a Weibull
distribution with ß = 0.5 and 6 = 3400. Determine the following in parts (a) and (b).
P(X >3500) =
a.
b.
P(X > 6000|X >3000) =
c. Suppose that Xhas an exponential distribution with mean equal to 3400. Determine
P(X 6000 X 3000) =](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe6f76b1b-4dc8-4fb6-ba6c-71c6e499db43%2F2a4005e0-0f5a-4b8c-a6f5-27242e9e85b2%2Fv8vgn5q_processed.png&w=3840&q=75)
Transcribed Image Text:Suppose that the lifetime of a component (in hours), X, is modeled with a Weibull
distribution with ß = 0.5 and 6 = 3400. Determine the following in parts (a) and (b).
P(X >3500) =
a.
b.
P(X > 6000|X >3000) =
c. Suppose that Xhas an exponential distribution with mean equal to 3400. Determine
P(X 6000 X 3000) =
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