Suppose that one in six smartphone users have fallen prey to cyber-attack. We use a sample of 218 smartphone users. a-1. What is the expected value and the standard error of the sample proportion? (Round "Expected value" to 2 decimal places and "Standard error" to 4 decimal places.) expected value= standard error= a-2. Is it appropriate to use the normal distribution approximation for the sample proportion? multiple choice Yes, because np ≥ 5 and n(1 - p) ≥ 5 Yes, because n ≥ 30 No, because np ≥ 5 and n(1 - p) ≥ 5 No, because n < 30 b. What is the probability that more than 18% of smartphone users in the sample have fallen prey to cyber-attack? (Round final answer to 2 decimal places.) probability=
Suppose that one in six smartphone users have fallen prey to cyber-attack. We use a sample of 218 smartphone users. a-1. What is the expected value and the standard error of the sample proportion? (Round "Expected value" to 2 decimal places and "Standard error" to 4 decimal places.) expected value= standard error= a-2. Is it appropriate to use the normal distribution approximation for the sample proportion? multiple choice Yes, because np ≥ 5 and n(1 - p) ≥ 5 Yes, because n ≥ 30 No, because np ≥ 5 and n(1 - p) ≥ 5 No, because n < 30 b. What is the probability that more than 18% of smartphone users in the sample have fallen prey to cyber-attack? (Round final answer to 2 decimal places.) probability=
A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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Question
Suppose that one in six smartphone users have fallen prey to cyber-attack. We use a sample of 218 smartphone users.
a-1. What is the
expected value=
standard error=
a-2. Is it appropriate to use the normal distribution approximation for the sample proportion?
multiple choice
-
Yes, because np ≥ 5 and n(1 - p) ≥ 5
-
Yes, because n ≥ 30
-
No, because np ≥ 5 and n(1 - p) ≥ 5
-
No, because n < 30
b. What is the probability that more than 18% of smartphone users in the sample have fallen prey to cyber-attack? (Round final answer to 2 decimal places.)
probability=
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