Suppose that the efficacy of a certain drug is 0.43. Consider the sampling distribution (sample size n = 180) for the proportion of patients cured by this drug. What is the mean of this distribution? 0.43 What is the standard error of this distribution? Round your answer to two decimal places. 0.57 X

MATLAB: An Introduction with Applications
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Author:Amos Gilat
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Suppose that the efficacy of a certain drug is 0.43. Consider the sampling distribution (sample size \( n = 180 \)) for the proportion of patients cured by this drug.

**What is the mean of this distribution?**

- The mean is \( 0.43 \) ✔️

**What is the standard error of this distribution? Round your answer to two decimal places.**

- Incorrect answer provided: \( 0.57 \) ❌

**Instructions:** Enter an integer or decimal number. [more...]

**Explanation:** 

The mean of the sampling distribution is equal to the population proportion \( p \), which is \( 0.43 \). The standard error (SE) of this distribution can be calculated using the formula for the standard error of a proportion:

\[
SE = \sqrt{\frac{p(1-p)}{n}}
\]

where \( p \) is the population proportion, and \( n \) is the sample size.
Transcribed Image Text:Suppose that the efficacy of a certain drug is 0.43. Consider the sampling distribution (sample size \( n = 180 \)) for the proportion of patients cured by this drug. **What is the mean of this distribution?** - The mean is \( 0.43 \) ✔️ **What is the standard error of this distribution? Round your answer to two decimal places.** - Incorrect answer provided: \( 0.57 \) ❌ **Instructions:** Enter an integer or decimal number. [more...] **Explanation:** The mean of the sampling distribution is equal to the population proportion \( p \), which is \( 0.43 \). The standard error (SE) of this distribution can be calculated using the formula for the standard error of a proportion: \[ SE = \sqrt{\frac{p(1-p)}{n}} \] where \( p \) is the population proportion, and \( n \) is the sample size.
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