You will need a z table and ONE of the z score formulas for this question. Pretend there is pre-employment test with normally distributed scores and a mean =50 and standard deviation =10. What score will land you in the top 10%? A. 62.85 B. 52.65 C. 52 D. 55.85
Inverse Normal Distribution
The method used for finding the corresponding z-critical value in a normal distribution using the known probability is said to be an inverse normal distribution. The inverse normal distribution is a continuous probability distribution with a family of two parameters.
Mean, Median, Mode
It is a descriptive summary of a data set. It can be defined by using some of the measures. The central tendencies do not provide information regarding individual data from the dataset. However, they give a summary of the data set. The central tendency or measure of central tendency is a central or typical value for a probability distribution.
Z-Scores
A z-score is a unit of measurement used in statistics to describe the position of a raw score in terms of its distance from the mean, measured with reference to standard deviation from the mean. Z-scores are useful in statistics because they allow comparison between two scores that belong to different normal distributions.
|
A. |
62.85 | |
| B. | 52.65 | |
| C. | 52 | |
| D. | 55.85 |
Provided information is ;
mean( )=50
standard deviation( )=10
level of significance ( ) = 10% = 0.1
From z table :
z score at 0.1 level of significance = 1.28 ................(right tailed)
thus ;
z =
where ;
x = observed score
=mean
=standard deviation
Trending now
This is a popular solution!
Step by step
Solved in 2 steps
