Psychology students at a university completed the Dental Anxiety Scale questionnaire. Scores on the scale range from 0 (no anxiety) to 20 (extreme anxiety). The mean score was 11 and the standard deviation was 3.5. Assume that the distribution of all scores on the Dental Anxiety Scale is normal with u=11 and o = 3.5. Complete parts a through c. E Click here to view a table of areas under the standardized normal curve. a. Suppose you score a 18 on the Dental Anxiety Scale. Find the z-value for this score. z= 2 (Round to the nearest hundredth as needed.) b. Find the probability that someone scores between 10 and 15 on the Dental Anxiety Scale. P(10sxs 15) = (Round to four decimal places as needed.) c. Find the probability that someone scores above 17 on the Dental Anxiety Scale. P(x>17) =O (Round to four decimal places as needed.)
Inverse Normal Distribution
The method used for finding the corresponding z-critical value in a normal distribution using the known probability is said to be an inverse normal distribution. The inverse normal distribution is a continuous probability distribution with a family of two parameters.
Mean, Median, Mode
It is a descriptive summary of a data set. It can be defined by using some of the measures. The central tendencies do not provide information regarding individual data from the dataset. However, they give a summary of the data set. The central tendency or measure of central tendency is a central or typical value for a probability distribution.
Z-Scores
A z-score is a unit of measurement used in statistics to describe the position of a raw score in terms of its distance from the mean, measured with reference to standard deviation from the mean. Z-scores are useful in statistics because they allow comparison between two scores that belong to different normal distributions.

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